vb.net操作TreeView控件,生成树节点的实例代码,其中遍历采用递归方法。
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- Public Class Form2
- Class nn
- Public name As String
- Public parent As String
- Public snumber As String
- End Class
- Private Sub Form2_Load(ByVal sender As Object,ByVal e As System.EventArgs) Handles Me.Load
- Dim nd(10) As nn
- Dim i As Integer
- For i = 0 To 8
- nd(i) = New nn
- Next
- nd(0).name = "root" : nd(0).parent = "0" : nd(0).snumber = "1"
- nd(1).name = "aaa" : nd(1).parent = "1" : nd(1).snumber = "2"
- nd(2).name = "bbb" : nd(2).parent = "1" : nd(2).snumber = "3"
- nd(3).name = "ccc" : nd(3).parent = "2" : nd(3).snumber = "4"
- nd(4).name = "ddd" : nd(4).parent = "3" : nd(4).snumber = "5"
- nd(5).name = "eee" : nd(5).parent = "2" : nd(5).snumber = "6"
- nd(6).name = "fff" : nd(6).parent = "2" : nd(6).snumber = "7"
- nd(7).name = "ggg" : nd(7).parent = "5" : nd(7).snumber = "8"
- Me.TreeView1.Nodes.Clear()
- For i = 0 To 7
- addto(nd(i),TreeView1.Nodes)
- Next
- End Sub
- Public Sub addto(ByVal nd As nn,ByVal nodes As TreeNodeCollection)
- Dim dd As TreeNode
- Dim tmpd As TreeNode
- If nd.parent = "0" Then
- tmpd = nodes.Add(nd.name)
- tmpd.ToolTipText = nd.snumber
- Exit Sub
- Else
- For Each dd In nodes
- If nd.parent = dd.ToolTipText Then
- tmpd = dd.Nodes.Add(nd.name)
- tmpd.ToolTipText = nd.snumber
- Exit Sub
- End If
- addto(nd,dd.Nodes)
- Next
- End If
- End Sub
- End Class
代码仅供参考,实际应用可灵活变更。