如何获取调用类的名称(在PHP中)

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  1. define('anActionType',1);
  2. $actionTypes = array(anActionType => 'anActionType');
  3. class core {
  4. public $callbacks = array();
  5. public $plugins = array();
  6. public function __construct() {
  7. $this->plugins[] = new admin();
  8. $this->plugins[] = new client();
  9. }
  10. }
  11. abstract class plugin {
  12. public function registerCallback($callbackMethod,$onAction) {
  13. if (!isset($this->callbacks[$onAction]))
  14. $this->callbacks[$onAction] = array();
  15.  
  16. global $actionTypes;
  17. echo "Calling $callbackMethod in $callbacksClass because we got {$actionTypes[$onAction]}" . PHP_EOL;
  18.  
  19. // How do I get $callbacksClass?
  20.  
  21. $this->callbacks[$onAction][] = $callbackMethod;
  22. }
  23. }
  24. class admin extends plugin {
  25. public function __construct() {
  26. $this->registerCallback('onTiny',anActionType);
  27. }
  28. public function onTiny() { echo 'tinyAdmin'; }
  29. }
  30. class client extends plugin {
  31. public function __construct() {
  32. $this->registerCallback('onTiny',anActionType);
  33. }
  34. public function onTiny() { echo 'tinyClient'; }
  35. }
  36. $o = new core();

$callbacksClass应该是admin或者client.或者我完全忘记了这一点,应该这样呢?应该注意的是,我只接受一个不需要我将类名作为参数发送到registerCallback方法的答案.

使用 get_class()
  1. $this->callbacks[$onAction][] = $callbackMethod;
  2. $className = get_class($this);
  3.  
  4. // Call callback method
  5. $className->$callbackMethod();

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