当我尝试使用
PHP的ftp_put函数上传文件时,之前它是错误的:
警告:ftp_put()[function.ftp-put]:无数据连接
现在,我尝试将被动模式放在:
ftp_pasv($conn_id,true);
然后出现错误:
警告:ftp_put()[function.ftp-put]:键入设置为I. in
ftp_login已正确完成,并表示已成功完成.
现在它给出了新警告:警告:ftp_put()[function.ftp-put]:abc.txt:无法打开或删除包含正在运行的程序的文件.
任何想法,为什么文件不转移?
谢谢 !
这是我的代码片段:
- $conn_id = ftp_connect($ftp_server) or die("Couldn't connect to $ftp_server");
- $login_result = ftp_login($conn_id,$ftp_user_name,$ftp_user_pass) or die("You do not have access to this ftp server!");
- if ((!$conn_id) || (!$login_result)) {
- // wont ever hit this,b/c of the die call on ftp_login
- echo "<span style='color:#FF0000'><h2>FTP connection has Failed! <br />";
- echo "Attempted to connect to $ftp_server for user $ftp_user_name</h2></span>";
- exit;
- } else {
- //echo "Connected to $ftp_server,for user $ftp_user_name <br />";
- }
- //turn passive mode on
- ftp_pasv($conn_id,true);
- $upload = ftp_put($conn_id,$destination_file.$name,$filename,FTP_BINARY);
- if (!$upload) {
- echo "<span style='color:#FF0000'><h2>FTP upload of $filename has Failed!</h2></span> <br />";
- } else {
- echo 'Uploaded';
- }
- ftp_close($conn_id);