$start = strtotime('20-04-2010 10:00');
$end   = strtotime('22-04-2010 10:00');
for($current = $start; $current <= $end; $current += 86400) {
    echo date('d-m-Y',$current);
}

10:00部分是为了防止代码由于夏令时而跳过或重复一天.

通过给出天数：

for($i = 0; $i <= 2; $i++) {
    echo date('d-m-Y',strtotime("20-04-2010 +$i days"));
}

用PHP5.3

$period = new DatePeriod(
    new DateTime('20-04-2010'),DateInterval::createFromDateString('+1 day'),new DateTime('23-04-2010') // or pass in just the no of days: 2
);
 
foreach ( $period as $dt ) {
  echo $dt->format( 'd-m-Y' );
}