如
Meta Question所述,Facebook接受我们密码的完全相反的案例变体.例如:
- 1.- paSSw5ORD (Original password)
- 2.- PAssW5ord (Case altered to exact opposite,Capital->Small and vice-versa.)
- 3.- PaSSw5ORD (Only first letter's case altered)
如何获得第二个变体,前提是第一个变体是原始变体,由用户输入(或者在用户输入第二个版本时获得第一个变体)?
这是我对此的看法.
- <?PHP
- $pass = "paSSw5ORD"; //Example password
- $pass_len = strlen($pass); //Find the length of string
- for($i=0;$i<$pass_len;$i++){
- if(!(is_numeric($pass[$i]))){ //If Not Number
- if($pass[$i]===(strtoupper($pass[$i]))){ //If Uppercase
- $pass2 .= strtolower($pass[$i]); //Make Lowercase & Append
- } else{ // If Lowercase
- $pass2 .= strtoupper($pass[$i]); //Make Uppercase & Append
- }
- } else{ //If Number
- $pass2 .= $pass[$i]; //Simply Append
- }
- }
- //Test both
- echo $pass."\r\n";
- echo $pass2;
- ?>
但是如何使用特殊字符处理密码(所有这些都可以在标准英文键盘上进行?
- !@#$%^&*()_+|?><":}{~[];',./ (Space also)
这不适用于所有上述特殊字符.
- if(preg_match('/^\[a-zA-Z]+$/',"passWORD")){
- //Special Character encountered. Just append it and
- //move to next cycle of loop,similar to when we
- //encountered a number in above code.
- }
我不是RegEx的专家,那么如何修改上面的RegEx以确保它处理所有上述特殊字符?
这是一个切换字符串中字符大小写的函数.
- <?PHP
- $string = "Hello"; // the string which need to be toggled case
- $string_length = strlen($string); // calculate the string length
- for($i=0;$i<$string_length;$i++){ // iterate to find ascii for each character
- $current_ascii = ord($string{$i}); // convert to ascii code
- if($current_ascii>64 && $current_ascii<91){ // check for upper case character
- $toggled_string .= chr($current_ascii+32); // replace with lower case character
- }elseif($current_ascii>96 && $current_ascii<123){ // check for lower case character
- $toggled_string .= chr($current_ascii-32); // replace with upper case character
- }else{
- $toggled_string .= $string{$i}; // concatenate the non alphabetic string.
- }
- }
- echo "The toggled case letter for $string is <hr />".$toggled_string; // output will be hELLO
- ?>
希望对你有帮助
在这个link中给出了相同的例子.