Javascript回调函数在Firefox中抛出错误“回调不是函数”

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  1. function CascadeDropDowns(parentClass,childClass,action,callback) {
  2. var DropDownId = $(parentClass + " option:selected").val();
  3.  
  4. $.ajax({
  5. url: "/site/" + action,data: { DropDownId: DropDownId },dataType: "json",type: "POST",error: function () {
  6. alert("An error occurred.");
  7. },success: function (data) {
  8. var items = "";
  9. $.each(data,function (i,item) {
  10. items += "<option value=\"" + item.Value + "\">" + item.Text + "</option>";
  11. });
  12. $(childClass).html(items);
  13. $(childClass)[0].selectedIndex = 0;
  14. callback();
  15. }
  16. });
  17. }
  18.  
  19. $(document).ready(function () {
  20. // Populates all child drop downs on load
  21. var callback = function () {
  22. CascadeDropDowns(".ConfigGroupDDL",".ConfigNameDDL","GetParameters");
  23. };
  24.  
  25. CascadeDropDowns(".DeviceTypeDDL",".ConfigGroupDDL","GetGroups",callback);
  26.  
  27. // Populates all child drop downs parent change
  28. $(".DeviceTypeDDL").change(function () {
  29. var callback = function () {
  30. CascadeDropDowns(".ConfigGroupDDL","GetParameters");
  31. };
  32. CascadeDropDowns(".DeviceTypeDDL",callback);
  33. });
  34. $(".ConfigGroupDDL").change(function () {
  35. CascadeDropDowns(".ConfigGroupDDL","GetParameters");
  36. });
  37. });
@H_404_4@这样运行正常,并以正确的顺序级联下拉列表,但是firefox调试器显示错误,即抛出一个警告,并询问Id liek是否进行调试.

@H_404_4@任何建议都会很棒

解决方法

这是因为您并不总是将回调传递给该方法.
  1. success: function (data) {
  2. var items = "";
  3. $.each(data,item) {
  4. items += "<option value=\"" + item.Value + "\">" + item.Text + "</option>";
  5. });
  6. $(childClass).html(items);
  7. $(childClass)[0].selectedIndex = 0;
  8. if(callback) callback(); //check before calling it.
  9. }

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