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Android how to sort JSONArray of JSONObjects6
如何按对象的字段排序对象的JSONArray?
如何按对象的字段排序对象的JSONArray?
输入:
- [
- { "ID": "135","Name": "Fargo Chan" },{ "ID": "432","Name": "Aaron Luke" },{ "ID": "252","Name": "Dilip Singh" }
- ];
- [
- { "ID": "432","Name": "Dilip Singh" }
- { "ID": "135",];
解决方法
尝试这个:
- //I assume that we need to create a JSONArray object from the following string
- String jsonArrStr = "[ { \"ID\": \"135\",\"Name\": \"Fargo Chan\" },{ \"ID\": \"432\",\"Name\": \"Aaron Luke\" },{ \"ID\": \"252\",\"Name\": \"Dilip Singh\" }]";
- JSONArray jsonArr = new JSONArray(jsonArrStr);
- JSONArray sortedJsonArray = new JSONArray();
- List<JSONObject> jsonValues = new ArrayList<JSONObject>();
- for (int i = 0; i < jsonArr.length(); i++) {
- jsonValues.add(jsonArr.getJSONObject(i));
- }
- Collections.sort( jsonValues,new Comparator<JSONObject>() {
- //You can change "Name" with "ID" if you want to sort by ID
- private static final String KEY_NAME = "Name";
- @Override
- public int compare(JSONObject a,JSONObject b) {
- String valA = new String();
- String valB = new String();
- try {
- valA = (String) a.get(KEY_NAME);
- valB = (String) b.get(KEY_NAME);
- }
- catch (JSONException e) {
- //do something
- }
- return valA.compareTo(valB);
- //if you want to change the sort order,simply use the following:
- //return -valA.compareTo(valB);
- }
- });
- for (int i = 0; i < jsonArr.length(); i++) {
- sortedJsonArray.put(jsonValues.get(i));
- }
排序的JSONArray现在存储在sortedJsonArray对象中.