尝试从UI
Image获取CI
Image以便将其用于CIFilter,但在最后一行获得以下异常：
- Execution was interrupted,reason: EXC_BREAKPOINT (code=EXC_I386_BPT,subcode=0x0)
我究竟做错了什么？
- import UIKit
- UIGraphicsBeginImageContextWithOptions(CGSizeMake(100,100),false,0)
- let con:CGContextRef = UIGraphicsGetCurrentContext()
- CGContextAddEllipseInRect(con,CGRectMake(0,100,100))
- CGContextSetFillColorWithColor(con,UIColor.blueColor().CGColor)
- CGContextFillPath(con)
- let im:UIImage = UIGraphicsGetImageFromCurrentImageContext()
- UIGraphicsEndImageContext()
- let ciimage = CIImage(image: im) // <- Exception here
更新：
根据不将CIImage实例化为变量的建议,我重新设计了我的初始代码片段,以便在游乐场中工作：
- UIGraphicsBeginImageContextWithOptions(CGSizeMake(100,UIColor.blueColor().CGColor)
- CGContextFillPath(con)
- let im:UIImage = UIGraphicsGetImageFromCurrentImageContext()
- UIGraphicsEndImageContext()
- //let ciimage = CIImage(image: im) // <- this was causing an exception
- let filter = CIFilter(name: "CIGaussianBlur",withInputParameters: [kCIInputRadiusKey: 10,kCIInputImageKey: CIImage(image: im)]) // <- this does not cause an exception
- let calayer = CALayer()
- calayer.contents = CIContext(options:nil).createCGImage(filter.outputImage,fromRect: filter.outputImage.extent())
- calayer.frame = CGRect(x: 0,y: 0,width: 270,height: 270)
- var view = UIView()
- view.frame = calayer.frame
- view.layer.addSublayer(calayer)
- XCPShowView("view",view)
解决方法
如果您正在尝试使用过滤器,我解决了这个操场错误：
- let pic = UIImage(named: "crumpled.jpg")
- let filter = CIFilter(name: "CISepiaTone")
- filter.setValue(CIImage(image: pic),forKey: kCIInputImageKey)
- filter.setValue(0.8,forKey: kCIInputIntensityKey)
- let ctx = CIContext(options:nil)
- let cgImage = ctx.createCGImage(filter.outputImage,fromRect:filter.outputImage.extent())
