我正在尝试创建一个具有透明度的自定义位图画笔,但它似乎没有按预期工作.如果你看一下这个例子.添加代码并连接绘制,创建和销毁事件.

type
  TForm3 = class(TForm)
    procedure FormDestroy(Sender: TObject);
    procedure FormCreate(Sender: TObject);
    procedure FormPaint(Sender: TObject);
  private
    FBitmap: TBitmap;
  end;
 
// Implementation
 
function CreateBlockBitmap(const APenColor: TColor): TBitmap;
begin
  Result := TBitmap.Create;
  Result.Transparent := True; 
  Result.Canvas.Brush.Color := clWhite;
  Result.Canvas.Brush.Style := bsClear;
  Result.PixelFormat := pf32bit;
  Result.SetSize(20,20);
  Result.Canvas.Brush.Color := APenColor;
  Result.Canvas.Brush.Style := bsSolid;
  Result.Canvas.FillRect(Rect(0,10,10));
end;
 
procedure TForm3.FormDestroy(Sender: TObject);
begin
  FBitmap.Free;
end;
 
procedure TForm3.FormCreate(Sender: TObject);
begin
  FBitmap := CreateBlockBitmap(clRed);
end;
 
procedure TForm3.FormPaint(Sender: TObject);
var
  colNum: Integer;
  rowNum: Integer;
begin
  // Paint the rectangle using the brush
  Canvas.Pen.Color := clGreen;
  Canvas.Brush.Bitmap := FBitmap; // This is using bitmap
  Canvas.Rectangle(50,50,250,250);
  // Draw the block using Canvas.Draw
  for rowNum := 0 to 9 do
    for colNum := 0 to 9 do
      Canvas.Draw(350 + rowNum * 20,50 + colNum * 20,FBitmap);
end;

此代码生成两个绘制的块.左边的一个使用位图画笔绘制,右边的一个使用Canvas.Draw调用绘制.

我需要刷涂上透明度,类似于使用舱口刷时会发生的情况.这个答案似乎表明它是可能的：

How can I draw a patternBrush with transparent backround (GDI)?

我试过的

1)我尝试使用纯色背景而不是使用bsClear.这只会使背景变白.

Result.Canvas.Brush.Color := clWhite;
  Result.Canvas.Brush.Style := bsSolid;

如果我使用clFuchsia,那么颜色是紫红色.我也尝试绘制背景clFuchsia,然后将TransparentColor设置为clFuchsia. Canvas.Draw选项使用透明度绘制,而画笔则不绘制.

2)我尝试使用以下代码直接设置alpha通道：

procedure SetAlphaBitmap(const Dest: TBitmap;Color : TColor;Alpha:Byte);
type
  TRGB32 = record
    B,G,R,A: byte;
  end;
  PRGBArray32 = ^TRGBArray32;
  TRGBArray32 = array[0..0] of TRGB32;
var
  x,y:    integer;
  Line,Delta: integer;
  ColorRGB : TColor;
begin
  if Dest.PixelFormat<>pf32bit then  exit;
 
  ColorRGB := ColorToRGB(Color);
  Line  := integer(Dest.ScanLine[0]);
  Delta := integer(Dest.ScanLine[1]) - Line;
  for y := 0 to Dest.Height - 1 do
  begin
    for x := 0 to Dest.Width - 1 do
      if TColor(RGB(PRGBArray32(Line)[x].R,PRGBArray32(Line)[x].G,PRGBArray32(Line)[x].B)) = ColorRGB then
        PRGBArray32(Line)[x].A := Alpha;
    Inc(Line,Delta);
  end;
end;

然后在使用背景颜色绘制矩形后立即调用此例程.

Result.Canvas.Brush.Style := bsSolid;
  Result.Canvas.FillRect(Rect(0,10));
  SetAlphaBitmap(Result,clBlack,0); // Set the alpha channel
end;

我知道alpha通道正在工作,因为如果我传入alpha值为255,那么它也会在Canvas.Draw中以黑色显示.

SetAlphaBitmap(Result,255);

3)我尝试通过创建模式画笔并分配而不是位图来进行测试.这产生了完全相同的结果. FBrush是HBRUSH.

FBrush := CreatePatternBrush(FBitmap.Handle);

并像这样设置画笔：

Canvas.Brush.Handle := FBrush;

4)我尝试调用SetBkMode,如上面的SO答案中所示.这没有任何区别.

Canvas.Pen.Color := clGreen;
  Canvas.Brush.Bitmap := FBitmap; 
  SetBkMode(Canvas.Handle,TRANSPARENT); // This doesn't make a difference
  Canvas.Rectangle(50,250);

编辑

5)我刚用单色位图测试,它有同样的问题.图像涂有白色背景和黑色前景用于画笔,透明用于Canvas.Draw.

function CreateMonochromeBitmap: TBitmap;
begin
  Result := TBitmap.Create;
  Result.Transparent := True;
  Result.Canvas.Brush.Color := clWhite;
  Result.Canvas.Brush.Style := bsSolid;
  Result.PixelFormat := pf1bit;
  Result.SetSize(20,20);
  Result.Canvas.Brush.Color := clBlack;
  Result.Canvas.Brush.Style := bsSolid;
  Result.Canvas.FillRect(Rect(0,10));
end;

在构造函数中：

FBitmap := CreateMonochromeBitmap;
FBrush := CreatePatternBrush(FBitmap.Handle);

在paint中我们设置句柄而不是位图属性.

Canvas.Brush.Handle := FBrush;