关于本篇文章，先参见本人之前的一篇博客，与之相关：

http://blog.csdn.net/kuzuozhou/article/details/7451289

另外，参考：

http://blog.csdn.net/ssjhust123/article/details/7754103

#include<stdio.h> 
#include <stdlib.h>
 
typedef struct node//节点存放一个数据和指向下一个节点的指针
{
	int data;
	struct node* pnext;
} Node;
 
Node *link_create()//链表创建
{
	int item;
	Node *head = NULL;
	do
	{
		Node *p;
		scanf("%d",&item);
		p = (Node *)malloc(sizeof(Node));
		if(p == NULL)
		{
			printf("memory applied Failed\n");
			break;
		}
		p->data = item;
		p->pnext = head;
		head = p;
	}while(getchar() != '\n');
	return head;
}
 
void link_show(Node *head)
{
	Node* p;
	p=head;
	while(p != NULL)
	{
		printf("%d ",p->data);
		p = p->pnext;
	}
	printf("\n");
}
 
void link_destroy(Node *head)
{
	Node* p;
	Node* tmp;
	p=head;
	while(p != NULL)
	{
		tmp = p->pnext;
		free(p);
		p = tmp;
	}
}
 
//Node *link_reverse(Node *head)
//{
//	Node *pre,*cur,*next;
//	/*head->pnext =NULL;*/
//
//	pre = head;
//	cur = pre->pnext;
//	next = cur->pnext;
//	head->pnext =NULL;//第一次的pre，cur，next
//
//	if(next == NULL)//链表只有两个节点,如果没有此语句，当链表确实只有两个节点时，就会发生错误。
//	{
//		cur->pnext = pre;
//		head = cur;
//		return head;
//	}
//
//	while(next->pnext != NULL)
//	{
//		cur->pnext = pre;//修改指针，每次循环修改一次
//
//		pre = cur;
//		cur = next;
//		next = next->pnext;
//	}//循环终止时，next->pnext == NULL
//	cur->pnext = pre;
//	next->pnext = cur;
//	head = next;
//	return head;
//
//}
 
void link_reverse(Node **headRef)//递归来实现链表逆序，相比上面注释的部分实现，显得相当简洁
{
	Node *first,*rest;
	if(*headRef == NULL)
		return;
	first = *headRef;
	rest = first->pnext;
	if(rest == NULL)
		return;
	link_reverse(&rest);
	first->pnext->pnext = first;
	first->pnext = NULL;
	*headRef = rest;
}
 
 
int main()
{
	Node *new_head=NULL;
	Node *head = link_create();
	link_show(head);
	//new_head = link_reverse(head);
	link_reverse(&head);
	link_show(new_head);
	link_destroy(new_head);
 
	//system("pause");
	return 0;
}