我正在为Android编写一个应用程序,用于从SHOUTcast mp3流中获取元数据.我正在使用我在网上找到的一个非常漂亮的课程,我稍微修改了一下,但我仍然有两个问题.
1)我必须不断ping服务器以使用TimerTask更新元数据.我不喜欢这种方法,但这是我能想到的.
2)当我的应用程序运行时,有一吨公吨的垃圾收集.删除TimerTask摆脱了垃圾收集问题所以我不确定我是做错了还是这是正常的.
这是我正在使用的课程:
public class IcyStreamMeta {
protected URL streamUrl;
private MapMetadata;
private boolean isError;
public IcyStreamMeta(URL streamUrl) {
setStreamUrl(streamUrl);
isError = false;
}
/**
* Get artist using stream's title
*
* @return String
* @throws IOException
*/
public String getArtist() throws IOException {
MapMetadata();
if (!data.containsKey("StreamTitle"))
return "";
try {
String streamTitle = data.get("StreamTitle");
String title = streamTitle.substring(0,streamTitle.indexOf("-"));
return title.trim();
}catch (StringIndexOutOfBoundsException e) {
return "";
}
}
/**
* Get title using stream's title
*
* @return String
* @throws IOException
*/
public String getTitle() throws IOException {
MapMetadata();
if (!data.containsKey("StreamTitle"))
return "";
try {
String streamTitle = data.get("StreamTitle");
String artist = streamTitle.substring(streamTitle.indexOf("-")+1);
return artist.trim();
} catch (StringIndexOutOfBoundsException e) {
return "";
}
}
public MapMetadata() throws IOException {
if (Metadata == null) {
refreshMeta();
}
return Metadata;
}
public void refreshMeta() throws IOException {
retreiveMetadata();
}
private void retreiveMetadata() throws IOException {
URLConnection con = streamUrl.openConnection();
con.setRequestProperty("Icy-MetaData","1");
con.setRequestProperty("Connection","close");
//con.setRequestProperty("Accept",null);
con.connect();
int MetaDataOffset = 0;
MapMetaint")) {
// Headers are sent via HTTP
MetaDataOffset = Integer.parseInt(headers.get("icy-Metaint").get(0));
} else {
// Headers are sent within a stream
StringBuilder strHeaders = new StringBuilder();
char c;
while ((c = (char)stream.read()) != -1) {
strHeaders.append(c);
if (strHeaders.length() > 5 && (strHeaders.substring((strHeaders.length() - 4),strHeaders.length()).equals("\r\n\r\n"))) {
// end of headers
break;
}
}
// Match headers to get Metadata offset within a stream
Pattern p = Pattern.compile("\\r\\n(icy-Metaint):\\s*(.*)\\r\\n");
Matcher m = p.matcher(strHeaders.toString());
if (m.find()) {
MetaDataOffset = Integer.parseInt(m.group(2));
}
}
// In case no data was sent
if (MetaDataOffset == 0) {
isError = true;
return;
}
// Read Metadata
int b;
int count = 0;
int MetaDataLength = 4080; // 4080 is the max length
boolean inData = false;
StringBuilder MetaData = new StringBuilder();
// Stream position should be either at the beginning or right after headers
while ((b = stream.read()) != -1) {
count++;
// Length of the Metadata
if (count == MetaDataOffset + 1) {
MetaDataLength = b * 16;
}
if (count > MetaDataOffset + 1 && count < (MetaDataOffset + MetaDataLength)) {
inData = true;
} else {
inData = false;
}
if (inData) {
if (b != 0) {
MetaData.append((char)b);
}
}
if (count > (MetaDataOffset + MetaDataLength)) {
break;
}
}
// Set the data
Metadata = IcyStreamMeta.parseMetadata(MetaData.toString());
// Close
stream.close();
}
public boolean isError() {
return isError;
}
public URL getStreamUrl() {
return streamUrl;
}
public void setStreamUrl(URL streamUrl) {
this.Metadata = null;
this.streamUrl = streamUrl;
this.isError = false;
}
public static MapMetadata(String MetaString) {
MapMetadata = new HashMapMetaParts = MetaString.split(";");
Pattern p = Pattern.compile("^([a-zA-Z]+)=\\'([^\\']*)\\'$");
Matcher m;
for (int i = 0; i < MetaParts.length; i++) {
m = p.matcher(MetaParts[i]);
if (m.find()) {
Metadata.put((String)m.group(1),(String)m.group(2));
}
}
return Metadata;
}
}
这是我的计时器:
private void getMeta() {
timer.schedule(new TimerTask() {
public void run() {
try {
icy = new IcyStreamMeta(new URL(stationUrl));
runOnUiThread(new Runnable() {
public void run() {
try {
artist.setText(icy.getArtist());
title.setText(icy.getTitle());
} catch (IOException e) {
e.printStackTrace();
} catch (StringIndexOutOfBoundsException e) {
e.printStackTrace();
}
}
});
} catch (MalformedURLException e) {
e.printStackTrace();
}
}
},5000);
}
非常感谢任何帮助!
最佳答案