Perl：通过转换为秒来计算天数

我试图计算从数据库中提取的两个日期之间的日历天数.我认为将日期转换为秒将是一个简单而正确的解决方案.

#!/usr/bin/perl
use warnings;
use strict;
use POSIX qw(strftime);
use Date::Parse;
 
my $minDate = "2016-03-27";
my $maxDate = "2016-06-15";
 
print "Format as extracted from db: mindate: $minDate and maxdate: $maxDate\n"; 
 
my ($dbYear,$dbMonth,$dbDay) = split ('-',$minDate);
my $datum = "$dbYear$dbMonth$dbDay";
my $minDateSec = str2time($datum);
 
($dbYear,$maxDate);
$datum = "$dbYear$dbMonth$dbDay";
my $maxDateSec = str2time($datum);
 
my $numCalDaysSec = ($maxDateSec-$minDateSec)/86400;
 
print "Min date in Seconds: $minDateSec\n";
print "Max date in Seconds: $maxDateSec\n";
print "Num days: $numCalDaysSec\n";

最初,我认为这种方法为我提供了可靠的结果：

bash-3.2$./testNumDays.pl
As extracted from db: mindate: 2016-06-14 and maxdate: 2016-06-15
Min date in Seconds: 1465855200
Max date in Seconds: 1465941600
Num days: 1
bash-3.2$./testNumDays.pl
As extracted from db: mindate: 2016-05-31 and maxdate: 2016-06-15
Min date in Seconds: 1464645600
Max date in Seconds: 1465941600
Num days: 15
bash-3.2$./testNumDays.pl
As extracted from db: mindate: 2016-03-28 and maxdate: 2016-06-15
Min date in Seconds: 1459116000
Max date in Seconds: 1465941600
Num days: 79
bash-3.2$./testNumDays.pl
As extracted from db: mindate: 2016-03-27 and maxdate: 2016-06-15
Min date in Seconds: 1459033200
Max date in Seconds: 1465941600
Num days: 79.9583333333333
bash-3.2$

显然,日期之间的日历日期数应该是整数.嗯,我做错了什么？为什么转换为秒不可靠？

由于我是一个Perl新手,我可能会忽略这一点.因此,非常欢迎任何帮助.

解决方法

一种方法是使用 Time::Piece核心模块：

use warnings;
use strict;
use Time::Piece qw();
 
my $t1 = Time::Piece->strptime('2016-03-27','%Y-%m-%d');
my $t2 = Time::Piece->strptime('2016-06-15','%Y-%m-%d');
my $seconds = $t2 - $t1;
print $seconds->days(),"\n";
 
__END__
 
80

Perl：通过转换为秒来计算天数

解决方法

猜你在找的Perl相关文章