我有一个包含一个struct和一个NSObject的结构体,我想序列化成一个NSData对象:
struct Packet { var name: String var index: Int var numberOfPackets: Int var data: NSData } var thePacket = Packet(name: name,index: i,numberOfPackets: numberOfPackets,data: packetData)
如何最好地将该Patch序列化为NSData,如何最佳地将其排序?
运用
var bufferData = NSData(bytes: & thePacket,length: sizeof(Packet))
只给我一个名字和数据的指针.我正在探索NSKeyedArchiver,但是我必须使Packet成为一个对象,我更希望保留一个结构体.
干杯
聂
没有得到任何反馈,这是我结束的解决方案:
原文链接:/swift/319698.html>为我的结构生成encode()和decode()函数
>将Int更改为Int64,因此Int在32位和64位平台上具有相同的大小
有一个没有String或Data的中间结构(ArchivedPacket),只有Int64
这是我的代码,我将非常感谢您的反馈,特别是如果有更少的麻烦的方式来做到这一点:
public struct Packet { var name: String var index: Int64 var numberOfPackets: Int64 var data: NSData struct ArchivedPacket { var index : Int64 var numberOfPackets : Int64 var nameLength : Int64 var dataLength : Int64 } func archive() -> NSData { var archivedPacket = ArchivedPacket(index: Int64(self.index),numberOfPackets: Int64(self.numberOfPackets),nameLength: Int64(self.name.lengthOfBytesUsingEncoding(NSUTF8StringEncoding)),dataLength: Int64(self.data.length)) var Metadata = NSData( bytes: &archivedPacket,length: sizeof(ArchivedPacket) ) let archivedData = NSMutableData(data: Metadata) archivedData.appendData(name.dataUsingEncoding(NSUTF8StringEncoding,allowLossyConversion: false)!) archivedData.appendData(data) return archivedData } func unarchive(data: NSData!) -> Packet { var archivedPacket = ArchivedPacket(index: 0,numberOfPackets: 0,nameLength: 0,dataLength: 0) let archivedStructLength = sizeof(ArchivedPacket) let archivedData = data.subdataWithRange(NSMakeRange(0,archivedStructLength)) archivedData.getBytes(&archivedPacket) let nameRange = NSMakeRange(archivedStructLength,Int(archivedPacket.nameLength)) let dataRange = NSMakeRange(archivedStructLength + Int(archivedPacket.nameLength),Int(archivedPacket.dataLength)) let nameData = data.subdataWithRange(nameRange) let name = NSString(data: nameData,encoding: NSUTF8StringEncoding) as! String let theData = data.subdataWithRange(dataRange) let packet = Packet(name: name,index: archivedPacket.index,numberOfPackets: archivedPacket.numberOfPackets,data: theData) return packet } }