Regex是否使用C#，VB.NET，Perl或任何语言。所以，不管你使用什么语言，与我们分享一两个具有挑战性的正则表达式。
重写这个怪物：
^(?:(?:(?:0?[13578]|1[02])(\/|-|\.)31)\1|(?:(?:0?[13-9]|1[0-2])(\/|-|\.)(?:29|30)\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:0?2(\/|-|\.)29\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$
更易读/可维护：
require 5.010;
my $sep = qr{ [/.-] }x; #allowed separators
my $any_century = qr/ 1[6-9] | [2-9][0-9] /x; #match the century
my $any_decade = qr/ [0-9]{2} /x; #match any decade or 2 digit year
my $any_year = qr/ $any_century? $any_decade /x; #match a 2 or 4 digit year
#match the 1st through 28th for any month of any year
my $start_of_month = qr/
(?: #match
0?[1-9] | #Jan - Sep or
1[0-2] #Oct - Dec
)
($sep) #the separator
(?:
0?[1-9] | # 1st - 9th or
1[0-9] | #10th - 19th or
2[0-8] #20th - 28th
)
\g{-1} #and the separator again
/x;
#match 28th - 31st for any month but Feb for any year
my $end_of_month = qr/
(?:
(?: 0?[13578] | 1[02] ) #match Jan,Mar,May,Jul,Aug,Oct,Dec
($sep) #the separator
31 #the 31st
\g{-1} #and the separator again
| #or
(?: 0?[13-9] | 1[0-2] ) #match all months but Feb
($sep) #the separator
(?:29|30) #the 29th or the 30th
\g{-1} #and the separator again
)
/x;
#match any non-leap year date and the first part of Feb in leap years
my $non_leap_year = qr/ (?: $start_of_month | $end_of_month ) $any_year/x;
#match 29th of Feb in leap years
#BUG: 00 is treated as a non leap year
#even though 2000,2400,etc are leap years
my $feb_in_leap = qr/
0?2 #match Feb
($sep) #the separtor
29 #the 29th
\g{-1} #the separator again
(?:
$any_century? #any century
(?: #and decades divisible by 4 but not 100
0[48] |
[2468][048] |
[13579][26]
)
|
(?: #or match centuries that are divisible by 4
16 |
[2468][048] |
[3579][26]
)
00
)
/x;
my $any_date = qr/$non_leap_year|$feb_in_leap/;
my $only_date = qr/^$any_date$/;