<div class="codebody" id="code76772">
<?PHP
$conn=@MysqL_connect("localhost","root","123") or die("服务器连接错误!"); //链接数据库
@MysqL_select_db("upload",$conn) or die("未发现数据库!");
$query="select * from upfile where ftag=$fn";
$result=MysqL_query($query);
if(!$result) die("error: MysqL query");
$num=MysqL_num_rows($result);
if($num<1) die("error: no this recorder");
$data = MysqL_result($result,"picture");
header("Content-type: image/JPEG",true);
echo $data;
?>