今天和大家分享一个获取10天后的一个时间戳的函数,程序的关键是,他可以不去算周六日哦。如果你有别的需求。可以改成N天的哦。反正就不算周六日。哈哈。
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//方法一:
PHP
$now = time(); //指定日期用法 $now = strtotime('2014-01-08') ;
$day = 3600*24;
$total = 12;
$days =array() ;
for ($i=2;$i<$total;$i++)
{
$timer = $now+$day$i;
$num= date("N",$timer)-2; //周一开始
if($num>=-1 and $num<=3)
{
if(count($days)>=10) break;
$days[]=date("Y-m-d",$now+$day$i);
$total +=1 ;// $total==12 ?$total+1:$total;
}else
{
$total = $total==12 ?$total+1:$total;
}
}
$i=1;
foreach($days as $day)
{
echo "$i===>".$day."\n";
$i++;
}
//方法二:
function get_days ($date="")
{
$now = empty($date)?time():strtotime($date);
$days = array();
$i = 2;
while(count($days)<10)
{
$timer = $now+360024$i;
$num= date("N",$timer)-2; //周一开始
if($num>=-1 and $num<=3)
{
$days[]=date("Y-m-d",$now+360024$i);
}
$i++;
}
return $days;
}