MySQL单表查询

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@H_301_3@目录

一、单表查询的语法及关键字执行的优先级

1.1 单表查询语法

SELECT DISTINCT 字段1,字段2... FROM 表名
                              WHERE 条件
                              GROUP BY field
                              HAVING 筛选
                              ORDER BY field
                              LIMIT 限制条数

1.2 关键字执行的优先级

  1. from:找到表
  2. where:拿着where指定的约束条件,去文件/表中取出一条条记录
  3. group by:将取出的一条条记录进行分组group by,如果没有group by,则整体作为一组
  4. select:执行select
  5. distinct:去重
  6. having:将分组的结果进行having过滤
  7. order by:将结果按条件排序:order by
  8. limit:限制结果的显示条数

二、简单查询

2.1 建表和数据准备

company.employee
    员工id      id                  int             
    姓名        emp_name            varchar
    性别        sex                 enum
    年龄        age                 int
    入职日期     hire_date           date
    岗位        post                varchar
    职位描述     post_comment        varchar
    薪水        salary              double
    办公室       office              int
    部门编号     depart_id           int



# 创建表
create table employee(
id int not null unique auto_increment,emp_name varchar(20) not null,sex enum('male','female') not null default 'male',#  大部分是男的
age int(3) unsigned not null default 28,hire_date date not null,post varchar(50),post_comment varchar(100),salary double(15,2),office int,#  一个部门一个屋子
depart_id int
);


# 查看表结构
MysqL> desc employee;
+--------------+-----------------------+------+-----+---------+----------------+
| Field        | Type                  | Null | Key | Default | Extra          |
+--------------+-----------------------+------+-----+---------+----------------+
| id           | int(11)               | NO   | PRI | NULL    | auto_increment |
| emp_name     | varchar(20)           | NO   |     | NULL    |                |
| sex          | enum('male','female') | NO   |     | male    |                |
| age          | int(3) unsigned       | NO   |     | 28      |                |
| hire_date    | date                  | NO   |     | NULL    |                |
| post         | varchar(50)           | YES  |     | NULL    |                |
| post_comment | varchar(100)          | YES  |     | NULL    |                |
| salary       | double(15,2)          | YES  |     | NULL    |                |
| office       | int(11)               | YES  |     | NULL    |                |
| depart_id    | int(11)               | YES  |     | NULL    |                |
+--------------+-----------------------+------+-----+---------+----------------+

# 插入记录
# 三个部门:教学,销售,运营
insert into employee(emp_name,sex,age,hire_date,post,salary,office,depart_id) values
('nick','male',18,'20170301','老男孩驻上海虹桥最帅',7300.33,401,1),#  以下是教学部
('jason',78,'20150302','teacher',1000000.31,('sean',81,'20130305',8300,('tank',73,'20140701',3500,('oscar',28,'20121101',2100,('mac','female','20110211',9000,('rocky','19000301',30000,('成龙',48,'20101111',10000,('歪歪','20150311','sale',3000.13,402,#  以下是销售部门
('丫丫',38,'20101101',2000.35,('丁丁','20110312',1000.37,('星星','20160513',3000.29,('格格','20170127',4000.33,('张野','20160311','operation',10000.13,403,3),#  以下是运营部门
('程咬金','19970312',20000,('程咬银','20130311',19000,('程咬铜','20150411',18000,('程咬铁','20140512',17000,3)
;

#  ps:如果在windows系统中,插入中文字符,select的结果为空白,可以将所有字符编码统一设置成gbk
# 简单查询
    SELECT id,emp_name,post_comment,depart_id 
    FROM employee;

    SELECT * FROM employee;

    SELECT emp_name,salary FROM employee;

# 避免重复DISTINCT
    SELECT DISTINCT post FROM employee;    

# 通过四则运算查询
    SELECT emp_name,salary*12 FROM employee;
    SELECT emp_name,salary*12 AS Annual_salary FROM employee;
    SELECT emp_name,salary*12 Annual_salary FROM employee;

# 定义显示格式
   CONCAT() 函数用于连接字符串
   SELECT CONCAT('姓名: ','  年薪: ',salary*12)  AS Annual_salary 
   FROM employee;
   
   CONCAT_WS() 第一个参数为分隔符
   SELECT CONCAT_WS(':',salary*12)  AS Annual_salary 
   FROM employee;

   结合CASE语句:
   SELECT
       (
           CASE
           WHEN emp_name = 'mac' THEN
               emp_name
           WHEN emp_name = 'jason' THEN
               CONCAT(emp_name,'_BIGSB')
           ELSE
               concat(emp_name,'SB')
           END
       ) as new_name
   FROM
       employee;

2.2 练习

  1. 查出所有员工的名字,薪资,格式为<名字:nick> <薪资:3000>
  2. 查出所有的岗位(去掉重复)
  3. 查出所有员工名字,以及他们的年薪,年薪的字段名为annual_year
select concat('<名字:','>    ','<薪资:','>') from employee;
select distinct depart_id from employee;
select emp_name,salary*12 annual_salary from employee;

三、约束条件(where)

where子句中可以使用:

  1. 比较运算符:> < >= <= <> !=
  2. between 80 and 100 值在80到100之间
  3. in(80,90,100) 值是80或90或100
  4. like 'n%'
    • 通配符可以是%或_,
      • %表示任意多字符
      • _表示一个字符
  5. 逻辑运算符:在多个条件直接可以使用逻辑运算符 and or not
1. 单条件查询
    SELECT emp_name FROM employee
        WHERE post='sale';
        
2. 多条件查询
    SELECT emp_name,salary FROM employee
        WHERE post='teacher' AND salary>10000;

3. 关键字BETWEEN AND
    SELECT emp_name,salary FROM employee 
        WHERE salary BETWEEN 10000 AND 20000;

    SELECT emp_name,salary FROM employee 
        WHERE salary NOT BETWEEN 10000 AND 20000;
    
4. 关键字IS NULL(判断某个字段是否为NULL不能用等号,需要用IS)
    SELECT emp_name,post_comment FROM employee 
        WHERE post_comment IS NULL;

    SELECT emp_name,post_comment FROM employee 
        WHERE post_comment IS NOT NULL;
        
    SELECT emp_name,post_comment FROM employee 
        WHERE post_comment=''; 注意''是空字符串,不是null
    ps:
        执行
        update employee set post_comment='' where id=2;
        再用上条查看,就会有结果了

5. 关键字IN集合查询
    SELECT emp_name,salary FROM employee 
        WHERE salary=3000 OR salary=3500 OR salary=4000 OR salary=9000 ;
    
    SELECT emp_name,salary FROM employee 
        WHERE salary IN (3000,4000,9000) ;

    SELECT emp_name,salary FROM employee 
        WHERE salary NOT IN (3000,9000) ;

6. 关键字LIKE模糊查询
    通配符’%’
    SELECT * FROM employee 
            WHERE emp_name LIKE 'ni%';

    通配符’_’
    SELECT * FROM employee 
            WHERE emp_name LIKE 'ja__';

3.1 练习

  1. 查看岗位是teacher的员工姓名、年龄
  2. 查看岗位是teacher且年龄大于30岁的员工姓名、年龄
  3. 查看岗位是teacher且薪资在9000-1000范围内的员工姓名、年龄、薪资
  4. 查看岗位描述不为NULL的员工信息
  5. 查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资
  6. 查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资
  7. 查看岗位是teacher且名字是jin开头的员工姓名、年薪
select emp_name,age from employee where post = 'teacher';
select emp_name,age from employee where post='teacher' and age > 30; 
select emp_name,salary from employee where post='teacher' and salary between 9000 and 10000;
select * from employee where post_comment is not null;
select emp_name,salary from employee where post='teacher' and salary in (10000,30000);
select emp_name,salary from employee where post='teacher' and salary not in (10000,salary*12 from employee where post='teacher' and emp_name like 'mac%';

四、分组(group by)

单独使用GROUP BY关键字分组
    SELECT post FROM employee GROUP BY post;
    注意:我们按照post字段分组,那么select查询的字段只能是post,想要获取组内的其他相关信息,需要借助函数

GROUP BY关键字和GROUP_CONCAT()函数一起使用
    SELECT post,GROUP_CONCAT(emp_name) FROM employee GROUP BY post;  # 按照岗位分组,并查看组内成员名
    SELECT post,GROUP_CONCAT(emp_name) as emp_members FROM employee GROUP BY post;

GROUP BY与聚合函数一起使用
    select post,count(id) as count from employee group by post;  #  按照岗位分组,并查看每个组有多少人

注意:如果我们用unique的字段作为分组的依据,则每一条记录自成一组,这种分组没有意义;多条记录之间的某个字段值相同,该字段通常用来作为分组的依据。

五、聚合函数

强调:聚合函数聚合的是组的内容,若是没有分组,则默认一组。

示例:

    SELECT COUNT(*) FROM employee;
    SELECT COUNT(*) FROM employee WHERE depart_id=1;
    SELECT MAX(salary) FROM employee;
    SELECT MIN(salary) FROM employee;
    SELECT AVG(salary) FROM employee;
    SELECT SUM(salary) FROM employee;
    SELECT SUM(salary) FROM employee WHERE depart_id=3;

5.1 练习

  1. 查询岗位名以及岗位包含的所有员工名字
  2. 查询岗位名以及各岗位内包含的员工个数
  3. 查询公司内男员工和女员工的个数
  4. 查询岗位名以及各岗位的平均薪资
  5. 查询岗位名以及各岗位的最高薪资
  6. 查询岗位名以及各岗位的最低薪资
  7. 查询男员工与男员工的平均薪资,女员工与女员工的平均薪资
题目1
MysqL> select post,group_concat(emp_name) from employee group by post;
+-----------------------------------------+---------------------------------------------------------+
| post                                    | group_concat(emp_name)                                      |
+-----------------------------------------+---------------------------------------------------------+
| operation                               | 张野,程咬金,程咬银,程咬铜,程咬铁                        |
| sale                                    | 歪歪,丫丫,丁丁,星星,格格                                |
| teacher                                 | jason,sean,tank,oscar,mac,rocky,成龙   |
| 老男孩驻上海虹桥最帅              | nick                                                    |
+-----------------------------------------+---------------------------------------------------------+


题目2
MysqL> select post,count(id) from employee group by post;
+-----------------------------------------+-----------+
| post                                    | count(id) |
+-----------------------------------------+-----------+
| operation                               |         5 |
| sale                                    |         5 |
| teacher                                 |         7 |
| 老男孩驻上海虹桥最帅              |         1 |
+-----------------------------------------+-----------+


题目3
MysqL> select sex,count(id) from employee group by sex;
+--------+-----------+
| sex    | count(id) |
+--------+-----------+
| male   |        10 |
| female |         8 |
+--------+-----------+

题目4
MysqL> select post,avg(salary) from employee group by post;
+-----------------------------------------+---------------+
| post                                    | avg(salary)   |
+-----------------------------------------+---------------+
| operation                               |  16800.026000 |
| sale                                    |   2600.294000 |
| teacher                                 | 151842.901429 |
| 老男孩驻上海虹桥最帅              |   7300.330000 |
+-----------------------------------------+---------------+

题目5
MysqL> select post,max(salary) from employee group by post;
+-----------------------------------------+-------------+
| post                                    | max(salary) |
+-----------------------------------------+-------------+
| operation                               |    20000.00 |
| sale                                    |     4000.33 |
| teacher                                 |  1000000.31 |
| 老男孩驻上海虹桥最帅              |     7300.33 |
+-----------------------------------------+-------------+

题目6
MysqL> select post,min(salary) from employee group by post;
+-----------------------------------------+-------------+
| post                                    | min(salary) |
+-----------------------------------------+-------------+
| operation                               |    10000.13 |
| sale                                    |     1000.37 |
| teacher                                 |     2100.00 |
| 老男孩驻上海虹桥最帅              |     7300.33 |
+-----------------------------------------+-------------+

题目7
MysqL> select sex,avg(salary) from employee group by sex;
+--------+---------------+
| sex    | avg(salary)   |
+--------+---------------+
| male   | 110920.077000 |
| female |   7250.183750 |
+--------+---------------+

六、过滤(having)

6.1 where和having的区别

执行优先级从高到低:where > group by > having

  1. Where 发生在分组group by之前,因而Where中可以有任意字段,但是绝对不能使用聚合函数
  2. Having发生在分组group by之后,因而Having中可以使用分组的字段,无法直接取到其他字段,可以使用聚合函数

6.1.1 验证

MysqL> select @@sql_mode;
+--------------------+
| @@sql_mode         |
+--------------------+
| ONLY_FULL_GROUP_BY |
+--------------------+
row in set (0.00 sec)

MysqL> select * from emp where salary > 100000;
+----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
| id | emp_name | sex  | age | hire_date  | post    | post_comment | salary     | office | depart_id |
+----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
|  2 | jason | male |  78 | 2015-03-02 | teacher | NULL         | 1000000.31 |    401 |         1 |
+----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
row in set (0.00 sec)

MysqL> select post,group_concat(emp_name) from emp group by post having salary > 10000;#错误,分组后无法直接取到salary字段
ERROR 1054 (42S22): Unknown column 'salary' in 'having clause'
MysqL> select post,group_concat(emp_name) from emp group by post having avg(salary) > 10000;
+-----------+-------------------------------------------------------+
| post | group_concat(emp_name) |
+-----------+-------------------------------------------------------+
| operation | 程咬铁,张野 |
| teacher | 成龙,jason |
+-----------+-------------------------------------------------------+
rows in set (0.00 sec)

6.2 练习

  1. 查询各岗位内包含的员工个数小于2的岗位名、岗位内包含员工名字、个数
  2. 查询各岗位平均薪资大于10000的岗位名、平均工资
  3. 查询各岗位平均薪资大于10000且小于20000的岗位名、平均工资
题目1
MysqL> select post,group_concat(emp_name),count(id) from employee group by post having count(id) < 2;
+-----------------------------------------+--------------------+-----------+
| post                                    | group_concat(emp_name) | count(id) |
+-----------------------------------------+--------------------+-----------+
| 老男孩驻上海虹桥最帅              | nick               |         1 |
+-----------------------------------------+--------------------+-----------+

题目2
MysqL> select post,avg(salary) from employee group by post having avg(salary) > 10000;
+-----------+---------------+
| post      | avg(salary)   |
+-----------+---------------+
| operation |  16800.026000 |
| teacher   | 151842.901429 |
+-----------+---------------+

题目3
MysqL> select post,avg(salary) from employee group by post having avg(salary) > 10000 and avg(salary) <20000;
+-----------+--------------+
| post      | avg(salary)  |
+-----------+--------------+
| operation | 16800.026000 |
+-----------+--------------+

七、查询排序(order by)

按单列排序
    SELECT * FROM employee ORDER BY salary;
    SELECT * FROM employee ORDER BY salary ASC;
    SELECT * FROM employee ORDER BY salary DESC;

按多列排序:先按照age排序,如果年纪相同,则按照薪资排序
    SELECT * from employee
        ORDER BY age,salary DESC;

7.1 练习

  1. 查询所有员工信息,先按照age升序排序,如果age相同则按照hire_date降序排序
  2. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资升序排列
  3. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资降序排列
题目1
MysqL> select * from employee ORDER BY age asc,hire_date desc;

题目2
MysqL> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) asc;
+-----------+---------------+
| post      | avg(salary)   |
+-----------+---------------+
| operation |  16800.026000 |
| teacher   | 151842.901429 |
+-----------+---------------+

题目3
MysqL> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) desc;
+-----------+---------------+
| post      | avg(salary)   |
+-----------+---------------+
| teacher   | 151842.901429 |
| operation |  16800.026000 |
+-----------+---------------+

八、限制查询的记录数(limit)

示例:

SELECT * FROM employee ORDER BY salary DESC 
    LIMIT 3;                    #默认初始位置为0 

SELECT * FROM employee ORDER BY salary DESC
    LIMIT 0,5; #从第0开始,即先出第一条,然后包含这一条在内往后查5条

SELECT * FROM employee ORDER BY salary DESC
    LIMIT 5,5; #从第5开始,即先出第6条,然后包含这一条在内往后查5条

8.1 练习

  1. 分页显示,每页5条
MysqL> select * from  employee limit 0,5;
+----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
| id | emp_name      | sex  | age | hire_date  | post                                    | post_comment | salary     | office | depart_id |
+----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
|  1 | nick      | male |  18 | 2017-03-01 | 老男孩驻上海虹桥最帅              | NULL         |    7300.33 |    401 |         1 |
|  2 | jason      | male |  78 | 2015-03-02 | teacher                                 |              | 1000000.31 |    401 |         1 |
|  3 | sean   | male |  81 | 2013-03-05 | teacher                                 | NULL         |    8300.00 |    401 |         1 |
|  4 | tank   | male |  73 | 2014-07-01 | teacher                                 | NULL         |    3500.00 |    401 |         1 |
|  5 | oscar | male |  28 | 2012-11-01 | teacher                                 | NULL         |    2100.00 |    401 |         1 |
+----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
rows in set (0.00 sec)

MysqL> select * from  employee limit 5,5;
+----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
| id | emp_name       | sex    | age | hire_date  | post    | post_comment | salary   | office | depart_id |
+----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
|  6 | mac | female |  18 | 2011-02-11 | teacher | NULL         |  9000.00 |    401 |         1 |
|  7 | rocky     | male   |  18 | 1900-03-01 | teacher | NULL         | 30000.00 |    401 |         1 |
|  8 | 成龙       | male   |  48 | 2010-11-11 | teacher | NULL         | 10000.00 |    401 |         1 |
|  9 | 歪歪       | female |  48 | 2015-03-11 | sale    | NULL         |  3000.13 |    402 |         2 |
| 10 | 丫丫       | female |  38 | 2010-11-01 | sale    | NULL         |  2000.35 |    402 |         2 |
+----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
rows in set (0.00 sec)

MysqL> select * from  employee limit 10,5;
+----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
| id | emp_name      | sex    | age | hire_date  | post      | post_comment | salary   | office | depart_id |
+----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
| 11 | 丁丁      | female |  18 | 2011-03-12 | sale      | NULL         |  1000.37 |    402 |         2 |
| 12 | 星星      | female |  18 | 2016-05-13 | sale      | NULL         |  3000.29 |    402 |         2 |
| 13 | 格格      | female |  28 | 2017-01-27 | sale      | NULL         |  4000.33 |    402 |         2 |
| 14 | 张野      | male   |  28 | 2016-03-11 | operation | NULL         | 10000.13 |    403 |         3 |
| 15 | 程咬金    | male   |  18 | 1997-03-12 | operation | NULL         | 20000.00 |    403 |         3 |
+----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
rows in set (0.00 sec)

九、使用正则表达式查询

SELECT * FROM employee WHERE emp_name REGEXP '^jas';

SELECT * FROM employee WHERE emp_name REGEXP 'on$';

SELECT * FROM employee WHERE emp_name REGEXP 'm{2}';


小结:对字符串匹配的方式
WHERE emp_name = 'nick';
WHERE emp_name LIKE 'sea%';
WHERE emp_name REGEXP 'on$';

9.1 练习

  1. 查看所有员工中名字是mac开头,n或者g结果的员工信息
select * from employee where emp_name regexp '^mac.*[gn]$';
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