有什么办法可以用UITapGestureRecognizer传递参数吗？
我已经看到这回答了 Objective-c但是找不到swift的答案
我已经看到这回答了 Objective-c但是找不到swift的答案
test.userInteractionEnabled = true
let tapRecognizer = UITapGestureRecognizer(target: self,action: Selector("imageTapped4:"))
// Something like text.myParamater
test.addGestureRecognizer(tapRecognizer)
然后在func imageTapped4(){}下接收myParameter
解决方法
一种方法是将UITapGestureRecognizer子类化,然后设置属性,我在下面发布了一个例子.您还可以检查发件人并检查是否等于某个标签,类,字符串,e.t.c
class ViewController: UIViewController {
@IBOutlet weak var label1: UILabel!
@IBOutlet weak var image: UIImageView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view,typically from a nib.
image.userInteractionEnabled = true;
let tappy = MyTapGesture(target: self,action: #selector(self.tapped(_:)))
image.addGestureRecognizer(tappy)
tappy.title = "val"
}
func tapped(sender : MyTapGesture) {
print(sender.title)
label1.text = sender.title
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
class MyTapGesture: UITapGestureRecognizer {
var title = String()
}
SO上有很多例子,看看,祝你好运.