我有一个以编程方式调用的UI
ImageView,我试图让它旋转但它不起作用.图像将被放置在动态UITableView中(我无法将其更改为静态).我的表视图中的图像看起来不错,但它不会旋转.
- (void)viewDidLoad
{
[super viewDidLoad];
UIImageView *imageView = [[UIImageView alloc] initWithFrame:CGRectMake(20,122,38,38)];
imageView.image = [UIImage imageNamed:@"settings1.png"];
[self.view addSubview:imageView];
CABasicAnimation *spin;
spin = [CABasicAnimation animationWithKeyPath:@"transform.rotation"];
spin.fromValue = [NSNumber numberWithFloat:0];
spin.toValue = [NSNumber numberWithFloat:((360*M_PI)/180)];
spin.duration = 4;
spin.repeatCount = 10*1000;
[imageView.layer addAnimation:spin forKey:@"360"];
解决方法
这可能是因为你试图在viewDidLoad中启动动画.我建议重新组织你的代码,使你在viewDidLoad中创建图像视图实例,但是等到viewDidAppear：被调用以实际启动动画.
@property (strong,nonatomic) UIImageView *imageView;
然后
- (void)viewDidLoad
{
[super viewDidLoad];
self.imageView = [[UIImageView alloc] initWithFrame:CGRectMake(20,38)];
self.imageView.image = [UIImage imageNamed:@"settings1.png"];
[self.view addSubview:self.imageView];
}
- (void)viewDidAppear:(BOOL)animated
{
[super viewDidAppear:animated];
CABasicAnimation *spin = [CABasicAnimation animationWithKeyPath:@"transform.rotation"];
spin.fromValue = [NSNumber numberWithFloat:0];
spin.toValue = [NSNumber numberWithFloat:((360*M_PI)/180)];
spin.duration = 4;
spin.repeatCount = 10*1000;
[self.imageView.layer addAnimation:spin forKey:@"360"];
}