从C#中触发并忘记Sql Server存储过程

C# 2019-09-30

我正在排队工作,在每项工作结束时,我想要启动一个SP,它将对数据进行大量处理.所以我不想等待SP完成,我只想在触发SP后立即转到下一个工作.存储过程将从触发代码中获取输入.

问题：-
这是我创建工作的脚本.请注意,我没有添加任何计划.

BEGIN TRANSACTION
DECLARE @ReturnCode INT
SELECT @ReturnCode = 0
IF NOT EXISTS (SELECT name FROM msdb.dbo.syscategories WHERE name=N'[Uncategorized (Local)]' AND category_class=1)
BEGIN
EXEC @ReturnCode = msdb.dbo.sp_add_category @class=N'JOB',@type=N'LOCAL',@name=N'[Uncategorized (Local)]'
IF (@@ERROR <> 0 OR @ReturnCode <> 0) GOTO QuitWithRollback

END

DECLARE @jobId BINARY(16)
EXEC @ReturnCode =  msdb.dbo.sp_add_job @job_name=N'job_JobName',@enabled=1,@notify_level_eventlog=0,@notify_level_email=0,@notify_level_netsend=0,@notify_level_page=0,@delete_level=0,@description=N'No description available.',@category_name=N'[Uncategorized (Local)]',@owner_login_name=N'UserName',@job_id = @jobId OUTPUT

IF (@@ERROR <> 0 OR @ReturnCode <> 0) GOTO QuitWithRollback
EXEC @ReturnCode = msdb.dbo.sp_add_jobstep @job_id=@jobId,@step_name=N'StepName',@step_id=1,@cmdexec_success_code=0,@on_success_action=1,@on_success_step_id=0,@on_fail_action=2,@on_fail_step_id=0,@retry_attempts=0,@retry_interval=0,@os_run_priority=0,@subsystem=N'Tsql',@command=N'exec dbo.SpToExecute',@database_name=N'DataBaseName',@flags=0
IF (@@ERROR <> 0 OR @ReturnCode <> 0) GOTO QuitWithRollback
EXEC @ReturnCode = msdb.dbo.sp_update_job @job_id = @jobId,@start_step_id = 1
IF (@@ERROR <> 0 OR @ReturnCode <> 0) GOTO QuitWithRollback
EXEC @ReturnCode = msdb.dbo.sp_add_jobserver @job_id = @jobId,@server_name = N'(local)'
IF (@@ERROR <> 0 OR @ReturnCode <> 0) GOTO QuitWithRollback
COMMIT TRANSACTION
GOTO EndSave
QuitWithRollback:
    IF (@@TRANCOUNT > 0) ROLLBACK TRANSACTION
EndSave:

现在,当我通过执行EXEC msdb.dbo.job_JobName’开始这项工作时,它没有执行dbo.SpToExecute.我需要在作业中只运行一次dbo.SpToExecute,然后作业应该停止.再次当我执行EXEC msdb.dbo.job_JobName’时,它应该再次运行exec dbo.SpToExecute一次.你能告诉我如何实现这个或我在这里缺少的东西吗？