现在我发现我可以使用Windows(XP)盒子中的PuTTY来解决它(很遗憾没有Linux机器)但不知怎的,当我在Mac上时,ssh [user @ ip]不接受我的密码.

与SFTP相同：WinSCP工作得很好,命令行SCP或任何像Cyber​​Duck这样的SFTP软件根本不起作用. (“错误的用户名或密码”)

我唯一的线索是OSX上的FileZilla能够在我设置它时使用不存在的编码进行连接.它抱怨编码无效,然后连接就好了.将编码设置为UTF-8或自动检测只会再次出现身份验证错误.

ServerFault,您是否知道如何让Mac连接到机器？非常感激.

编辑：这是ssh -v的输出：

Angua:~ winsmith$ssh -v web96_rootmaster@IPADDRESS
OpenSSH_5.2p1,OpenSSL 0.9.8l 5 Nov 2009
debug1: Reading configuration data /etc/ssh_config
debug1: Connecting to IPADDRESS [IPADDRESS] port 22.
debug1: Connection established.
debug1: identity file /Users/winsmith/.ssh/identity type -1
debug1: identity file /Users/winsmith/.ssh/id_rsa type -1
debug1: identity file /Users/winsmith/.ssh/id_dsa type 2
debug1: Remote protocol version 2.0,remote software version OpenSSH_5.1p1 Debian-5
debug1: match: OpenSSH_5.1p1 Debian-5 pat OpenSSH*
debug1: Enabling compatibility mode for protocol 2.0
debug1: Local version string SSH-2.0-OpenSSH_5.2
debug1: SSH2_MSG_KEXINIT sent
debug1: SSH2_MSG_KEXINIT received
debug1: kex: server->client aes128-ctr hmac-md5 none
debug1: kex: client->server aes128-ctr hmac-md5 none
debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent
debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP
debug1: SSH2_MSG_KEX_DH_GEX_INIT sent
debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY
debug1: Host 'IPADDRESS' is known and matches the RSA host key.
debug1: Found key in /Users/winsmith/.ssh/known_hosts:22
debug1: ssh_rsa_verify: signature correct
debug1: SSH2_MSG_NEWKEYS sent
debug1: expecting SSH2_MSG_NEWKEYS
debug1: SSH2_MSG_NEWKEYS received
debug1: SSH2_MSG_SERVICE_REQUEST sent
debug1: SSH2_MSG_SERVICE_ACCEPT received
debug1: Authentications that can continue: publickey,keyboard-interactive
debug1: Next authentication method: publickey
debug1: Trying private key: /Users/winsmith/.ssh/identity
debug1: Trying private key: /Users/winsmith/.ssh/id_rsa
debug1: read PEM private key done: type RSA
debug1: Authentications that can continue: publickey,keyboard-interactive
debug1: Offering public key: /Users/winsmith/.ssh/id_dsa
debug1: Authentications that can continue: publickey,keyboard-interactive
debug1: Next authentication method: keyboard-interactive
Password: 
debug1: Authentications that can continue: publickey,keyboard-interactive
Password:

说实话,我找不到任何线索.还有其他人吗？