使用^符号输入带有参数的多行命令时使用双引号来使用带空格的字符串^符号也会被传递,有人可以解释这是什么方式吗?
@H_502_20@
问题是,第二行开头的引号将被多行插入符号转义.
working.cmd
@echo off call openfiles.cmd ^ C:\dir\filename.txt ^ C:\another_dir\another_file.txt
notworking.cmd
@echo off call openfiles.cmd ^ "C:\dir with spaces\file with spaces.txt" ^ "C:\another dir with spaces\another file with spaces.txt"
openfiles.cmd看起来像
@echo off for %%x in (%*) do ( IF EXIST %%x ( call "c:\Program Files\Notepad++\notepad++.exe" %%x ) ELSE ( call echo Not found %%x ) ) pause
我得到的错误
C:\>call openfiles.cmd "C:\dir with spaces\file with spaces.txt" ^ ELSE was unexpected at this time.
因此,行中的最后一个引号开始引用而不是停止引用,因此第二行中的插入符号作为普通字符处理.
call openfiles.cmd ^"C:\dir with spaces\file with spaces.txt" ^ **This is a seperate line** "C:\another dir with spaces\another file with spaces.txt"
插入符号规则:
插入符号逃脱了下一个角色,因此角色会失去所有特效.
如果下一个字符是换行符,则删除此字符并取下一个字符(即使这也是换行符).
通过这个简单的规则,你可以解释像
echo #1 Cat^&Dog echo #2 Cat^ &Dog echo #3 Redirect to > Cat^ Dog setlocal EnableDelayedExpansion set lineFeed=^ echo #4 line1!lineFeed!line2
#3创建了一个名为“Cat Dog”的文件,因为空间已被转义,不再作为分隔符.
但它仍有可能打破这个规则!
你只需要在插入符号前面放置任何重定向,它仍然会丢弃换行符(多行仍然有效),但下一个字符不再被转义.
echo #5 Line1< nul ^ & echo Line2
所以你也可以使用它来构建你的多线命令
call openfiles.cmd < nul ^ "C:\dir with spaces\file with spaces.txt" < nul ^ "C:\another dir with spaces\another file with spaces.txt"
或者使用宏
set "\n=< nul ^" call openfiles.cmd %\n% "C:\dir with spaces\file with spaces.txt" %\n% "C:\another dir with spaces\another file with spaces.txt"