vb.net FormatNumber用法

前端之家收集整理的这篇文章主要介绍了vb.net FormatNumber用法前端之家小编觉得挺不错的,现在分享给大家,也给大家做个参考。
Title Use the FormatNumber function in Visual Basic .NET
Description This example shows how to use the FormatNumber function in Visual Basic .NET.
Keywords FormatNumber,format number,VB.NET
Categories Strings,VB.NET
The FormatNumber function returns a formatted string representation for a number. The Syntax is: @H_301_40@ FormatNumber(expression _ [,digits_after_decimal] _ [,include_leading_zero] _ [,use_parens_if_negative] _ [,groups_digits] )

Where:

expression
The numeric expression to format
digits_after_decimal
The number of digits to display after the decimal point
include_leading_zero
If the number is less than 1 and greater than -1,determines whether the number should have a leading 0 before the decimal point.
use_parens_if_negative
Determines whether negative numbers are surrounded with parentheses instead of using a minus sign.
groups_digits
Determines whether digits to the left of the decimal point are grouped with thousands separators (commas in the United States).

Examples:

Expression Result
FormatNumber(1.23456,2) 1.23
FormatNumber(0.123456,2,TriState.False) .12
FormatNumber(0.123456,TriState.True) 0.12
FormatNumber(-12345.12,TriState.False) -12,345.12
FormatNumber(-12345.12,TriState.True) (12,345.12)
FormatNumber(-12345.12,TriState.True,TriState.False) (12345.12)

This example uses the following code to display these examples in a TextBox.

@H_301_40@ @H_301_40@Private Sub Form1_Load(ByVal sender As System.Object,ByVal _ e As System.EventArgs) Handles MyBase.Load Dim txt As String Dim x As Single x = 1.23456 txt &= "FormatNumber(" & x.ToString() & ",2) = " & _ FormatNumber(x,2) & vbCrLf x = 0.123456 txt &= "FormatNumber(" & x.ToString() & "," & _ "TriState.False) = " & FormatNumber(x,_ TriState.False) & vbCrLf txt &= "FormatNumber(" & x.ToString() & "," & _ "TriState.True) = " & FormatNumber(x,_ TriState.True) & vbCrLf x = -12345.12345 txt &= "FormatNumber(" & x.ToString() & ",_ TriState.True) & vbCrLf txt &= "FormatNumber(" & x.ToString() & "," & _ "TriState.True,TriState.False) = " & _ FormatNumber(x,TriState.False) _ & vbCrLf txtResult.Text = txt txtResult.Select(0,0) End Sub
原文链接:https://www.f2er.com/vb/260956.html

猜你在找的VB相关文章