vb截取任意两个特征字符之间的字符…

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vb截取字符串

(1)左部截取left$(字符串,n):n是要截取的字符个数
(2)中部截取Mid$(字符串,p,n):表示从第p个字符开始截取n个字符
(3)右部截取Right$(字符串,n):表示截取字符串的后n个字符
如:
left$("abcdefg",3)的结果是:"abc"
mid$("abcdefg",2,3)的结果是:"bcd"
right$("abcdefg",3)的结果是:"efg"

Dim strSrc As String
Dim strResult As String

strSrc = "0|下载地址1|/upload/upload2/files/1.text"
strResult = Right(strSrc,Len(strSrc) - InStr(1,strSrc,"/"))

二、

vb截取任意两个 特征字符之间的字符串
111111+22222+33333333+44444+55555+66666…

如何得到任意两个符号”+”之间的字符串,譬如22222

以下为代码全过程,函数为增强版,支持任意字符,只需要在调用的时候修改参数就OK了,代码注释中已经有描述:
新建工程在窗体上放置两个TextBox控件和一个Command控件,名称不需要修改默认就OK,分别名为:text1.text text2.text 和 command1
然后复制以下代码:

Private Sub Command1_Click()
Text2.Text = GetChar(Trim(Text1.Text),"+",1,3)
End Sub
'函数使用方法: getchar(mStr:原始字符,charX:规律字符,比如截取两段加号之间的那么就输入"+",
'BofNum: 起始字符位,EofNum: 终点字符位)
Private Function GetChar(mStr As String,charX As String,BofNum As Integer,EofNum As Integer) As String
Dim i As Integer '循环
Dim x As Integer '记录第几个"+"符号
Dim startNum As Integer 'MID函数截取开始位数
Dim endNum As Integer 'MID函数截取结束位数
For i = 1 To Len(mStr)
If x = EofNum Then Exit For '得到截取开始和结束位数则退出
If Mid(mStr,i,1) = charX Then
x = x + 1
If x = BofNum Then '第一个为开始位置
startNum = i
ElseIf x = EofNum Then '第二为结束位置
endNum = i
End If
End If
Next i

'qnames2 = finddoc.MTnames
Dim sArray() As String
'Dim i As Integer '循环
Dim iCount As Integer '记录第几个"+"符号
iCount = 1
'For i = 1 To Len(qnames)
' sArray(i-1)= Mid(qnames,iCount,1)
' iCount =iCount + 2
' MsgBox sArray(i-1)
'Next
'开始位置第一个是符号 需要移动一位 结束位置-开始位置=截取长度
'截取出来的两边各有符号 所以需要取舍
GetChar = Mid(mStr,startNum + 1,endNum - startNum - 1) '赋值
End Function
三、mid()函数
aa="abcdA123456Bdff"

asite = instr(aa,"A")

bsite = instrRev(aa,"B")

Response.Write(mid(aa,asite+1,bsite-asite-1))

-----------------------------------------
function cutstr(byval str1 as string,byval StartStr as string,byval EndStr as string) as string
dim i as integer,j as integer,L1 as integer,L2 as integer
l1=len(startstr)
l2=len(endstr)
i=instr(str,startStr)
j=instr(str,endStr)
if (l1*l2=0) or (i*j=0) or (j-i<1) then '如果指定起始字符串与结束字符串有一个为空,或者有一个不存在,或者前后位置不正确,返回源字符串
cutstr=str1
exit function
else
cutstr=mid(str1,i+l1,j-l1-i)
end if
end function

dim str as string,s1 as string,s2 as string,s3 as string
str="[name]ASDADASDSA[year]123456789[number]123456"
s1="[name]"
s2="[year]"
s3="[number]"
msgBox cutstr(str,s1,s2)
msgBox cutstr(str,s2,s3)
---------------------------------------
dim str
wstr=[name]ASDADASDSA[year]123456789[number]123456
str=mid(wstr,instr(wstr,"[name]"),InStrRev(wstr,"[year]") - InStr(wstr,"[name]"))
str1=mid(wstr,"[year]"),"[number]") - InStr(wstr,"[year]"))
-------------------------------------


Private Sub Form_Click()
s = "[name]ASDADASDSA[year]123456789[number]123456"
a = Split(s,"]")
For i = 1 To UBound(a)
Print Split(a(i),"[")(0)
Next
End Sub

-----------
4.更高级的方法,使用正则表达式处理,正则表达式稍微复杂一些,有基础的朋友可以使用。
原文链接:https://www.f2er.com/vb/257093.html

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