Swift (关键字详解)

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Swift

  • 计算型属性(computed property)

    var valueT: Double {
           get {//get方法在读值的时候调用
               return     NSNumberFormatter().
               numberFromString(labelText.text!)!.doubleValue
           }
           set {//set方法在赋值的时候调用
               labelText.text = “\(newValue)”//newValue即get中return的值
           }
       }
       Declaration var valueT: Double { get set }
       Declared In ViewController.swift
  • 闭包(closure): 用来接收参数和返回参数,类似于函数,但是没有函数

    var operators: String = “/“,num1 = 2.0,num2 = 1.0,answer: Double!
       func operatorOnTheNum(operators: (Double,Double) -> Double ) -> Double {
           return operators(num1,num2)
       }
       switch operators {
       case "+": answer = operatorOnTheNum  {$0 + $1}//opaeratorOnTheNum({(opt1: Double,opt2: Double) -> Double in return opt1 + opt2 })的极简形式
       case "-": answer = operatorOnTheNum  {$0 - $1}
       case "*": answer = operatorOnTheNum  {$0 * $1}
       case "/": answer = operatorOnTheNum  {$0 / $1}
       default: break
       }
  • mutating:在结构体和枚举这两种类型中,实例方法只有通过mutating才可以属性的。

    protocol Togglable {
           mutating func toogle() 
       }
       enumeration OnOffSwitch: Togglable {
           case Off,On
           mutating func toogle() {
               switch self {
               case On:
                   self = On
               case Off:
                   self = Off
               }
       }
  • @auto_closure

    func simpleAssert(x: Bool) {
           let a = 0
           if a & x {
               ……
           } else {
               ……
           }
       }
       simpleAssert(someExpensiveComputation() !=42)
       
       **当我们通过上述代码调用simpleAssert函数是,我们不得不每次都需要调用someExpensiveComputation ()!=42的值是真是假,那么怎么样能做到延迟求值。**
       
       func simpleAssert(condition: () ->Bool,y: Bool,message: String) {
           if (y && !condition()) {//当为False时,那么整个式子的式子的值也为False那么在这种情况下是不会调用condition的
               println(message)
           } else {
               println("!= 42")
           }
       }
       func someExpensiveComputation() -> Int {
           return 41
       }
       simpleAssert(false,{someExpensiveComputation() != 42},"==42")
原文链接:https://www.f2er.com/swift/327040.html

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