我需要从AddressBook框架转换此函数的返回值：
ABRecordCopyValue(nil,kABPersonPhoneProperty)
值为ABMultiValueRef类型
func ABRecordCopyValue(record: ABRecordRef!,property: ABPropertyID) -> Unmanaged<AnyObject>!
所以我可以把它转换为非管理像这样：
ABRecordCopyValue(person,kABPersonPhoneProperty) as Unmanaged<ABMultiValueRef>
但是如何才能将其作为ABMultiValueRef获取,以便我可以将其传递给此函数？
func ABMultiValueGetIndexForIdentifier(multiValue: ABMultiValueRef!,identifier: ABMultiValueIdentifier) -> CFIndex
我做到了
let managedPhones = Unmanaged.fromOpaque(phones.toOpaque()).takeUnretainedValue() as ABMultiValueRef
我不断得到这个编译器错误：
Bitcast requires both operands to be pointer or neither %89 = bitcast %objc_object* %88 to %PSs9AnyObject_,!dbg !325 LLVM ERROR: Broken function found,compilation aborted! Command /Applications/Xcode6-Beta3.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/swift Failed with exit code 1
我找到了解决方案：
原文链接：https://www.f2er.com/swift/319844.htmlfunc peoplePickerNavigationController(
peoplePicker: ABPeoplePickerNavigationController!,didSelectPerson person: ABRecordRef!) {
/* Do we know which picker this is? */
if peoplePicker != personPicker{
return
}
/* Get all the phone numbers this user has */
let unmanagedPhones = ABRecordCopyValue(person,kABPersonPhoneProperty)
let phones: ABMultiValueRef =
Unmanaged.fromOpaque(unmanagedPhones.toOpaque()).takeUnretainedValue()
as NSObject as ABMultiValueRef
let countOfPhones = ABMultiValueGetCount(phones)
for index in 0..<countOfPhones{
let unmanagedPhone = ABMultiValueCopyValueAtIndex(phones,index)
let phone: String = Unmanaged.fromOpaque(
unmanagedPhone.toOpaque()).takeUnretainedValue() as NSObject as String
println(phone)
}
}
