我有一个字符串描述来保存我的句子.我只想把第一个字母大写.我尝试了不同的东西,但大多数都给了我例外和错误.我正在使用
Xcode 6.
这是我到目前为止所尝试的
let cap = [description.substringToIndex(advance(0,1))] as String
description = cap.uppercaseString + description.substringFromIndex(1)
它给了我：类型’String.Index’不符合协议’IntegerLiteralConvertible’
我试过了
func capitalizedStringWithLocale(locale:0) -> String
但我无法弄清楚如何让它发挥作用.
有任何想法吗？
import Foundation // A lowercase string let description = "the quick brown fox jumps over the lazy dog." // The start index is the first letter let first = description.startIndex // The rest of the string goes from the position after the first letter // to the end. let rest = advance(first,1)..<description.endIndex // Glue these two ranges together,with the first uppercased,and you'll // get the result you want. Note that I'm using description[first...first] // to get the first letter because I want a String,not a Character,which // is what you'd get with description[first]. let capitalised = description[first...first].uppercaseString + description[rest] // Result: "The quick brown fox jumps over the lazy dog."
您可能希望确保在开始之前句子中至少有一个字符,否则您将在尝试将索引超出字符串末尾时遇到运行时错误.
