我正在尝试执行此查询：
码：
this.getHibernateTemplate()
find("select distinct ci.customer " +
"from CustomerInvoice ci " +
"where ci.id in (?) ",ids);
将id作为List,id的类型为Long
执行时我得到例外
码：
java.lang.ClassCastException: java.util.ArrayList cannot be cast to java.lang.Long
at org.hibernate.type.LongType.set(LongType.java:42)
at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:136)
at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:116)
at org.hibernate.param.PositionalParameterSpecification.bind(PositionalParameterSpecification.java:39)
at org.hibernate.loader.hql.QueryLoader.bindParameterValues(QueryLoader.java:491)
at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1563)
at org.hibernate.loader.Loader.doQuery(Loader.java:673)
at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:236)
at org.hibernate.loader.Loader.doList(Loader.java:2220)
at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2104)
at org.hibernate.loader.Loader.list(Loader.java:2099)
at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:378)
at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:338)
at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:172)
at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1121)
at org.hibernate.impl.QueryImpl.list(QueryImpl.java:79)
at org.springframework.orm.hibernate3.HibernateTemplate$29.doInHibernate(HibernateTemplate.java:849)
at org.springframework.orm.hibernate3.HibernateTemplate.execute(HibernateTemplate.java:372)
at org.springframework.orm.hibernate3.HibernateTemplate.find(HibernateTemplate.java:840)
at org.springframework.orm.hibernate3.HibernateTemplate.find(HibernateTemplate.java:836)
at
最佳答案
除了mR_fr0g的答案之外,这个还有效：
原文链接：https://www.f2er.com/spring/432025.htmlthis.getHibernateTemplate()
findByNamedParam("select distinct ci.customer " +
"from CustomerInvoice ci " +
"where ci.id in (:ids) ","ids",ids);
