我有一组用户,我想测试一些可以在控制器规格中执行的操作.当每个用户被创建时,都有一组回调来创建关联的对象.

我想访问这些用户实例和该ActiveRecord类的关联对象.因此,例如,用户将有一组列表,以便我可以调用user1.lists.

另外,我想在顶部隔离这个设置,并使用我们的或前一个黑色.似乎只是这样打电话：

# will test that get_count_for_list will return 5
describe ApiController do

  # why same name - seems really confusing!
  let(:user) { FactoryGirl.create(:user) }
  let(:user2) { FactoryGirl.create(:user2) }

不会调用相关联的回调.它是否正确？还是可能是时间问题？

我喜欢使用let和能够访问我的ExampleGroups(如user.id)中的这些对象的语法,但无法访问user.lists.目前我正在做的事情是：

# will test that get_count_for_list will return 5

describe ApiController do

  # why same name - seems really confusing!
  let(:user) { FactoryGirl.create(:user) }
  let(:user2) { FactoryGirl.create(:user2) }
  let(:user3) { FactoryGirl.create(:user3) }

  before do
    FactoryGirl.create(:user2)
    FactoryGirl.create(:user3)
  end

但觉得必须有一个更好的方法.我是否创建了这两个用户？

谢谢

编辑1

我在这里分离了有关的代码. global_id值是通过回调创建的.它在db中正确存在,可以通过相应的find_by_email进行访问,但使用user2 var不提供访问权限.

require 'spec_helper'

# will test that get_count_for_list will return 5
describe ApiController do
  # why same name - seems really confusing!
  let!(:user) { FactoryGirl.create(:user) }
  let!(:user2) { FactoryGirl.create(:user2) }
  let!(:user3) { FactoryGirl.create(:user3) }



  before do
    session[:user_id]=user.id # works
  end

  describe 'FOLLOW / UNFOLLOW options' do
    it 'shall test the ability to follow another user' do
      puts "user1: " + user.global_id.to_s # doesn't output anything
      u2=User.find_by_email('jo@jo.com') # corresponds to user2
      post :follow,:global_id => user2.global_id # doesn't work
      #post :follow,:global_id => u2.global_id  #works


      u3=User.find_by_email('su@su.com')
      puts "user_3" + u3.global_id.to_s # outputs correct value

      post :follow,:global_id => user3.global_id  #doesn't work
      #post :follow,:global_id => u3.global_id # works


      post :unfollow,:global_id => user.following.sample(1)
      response.code.should eq('200')
    end
  end
end