ruby-on-rails – Rails 4删除嵌套属性,适用于创建,但不能编辑/更新

前端之家收集整理的这篇文章主要介绍了ruby-on-rails – Rails 4删除嵌套属性,适用于创建,但不能编辑/更新前端之家小编觉得挺不错的,现在分享给大家,也给大家做个参考。
所以我正在从这个 Railscast工作.

而且,我知道Rails 4的Strong参数有一些变化.

First relevant question.

Second relevant question

我已经检查了我的实现四倍,但看不到我出错了.正如现在一样,在最初提交病人时(即创建方法)打勾时,勾选“破坏”框,并按照预期的方式工作,并删除任何具有复选框的药物,并允许任何不在(从三个表单输入它提供).

然而,当我随后编辑该病人时,任何未被检查被删除的药物都被复制(所以我最终得到的药物比我开始使用的更多),任何被检查的药物似乎都没有改变.

所以如果有两种药物附有“Med1”和“Med2”,我编辑病人,如果两者都被标记删除,我仍然会以“Med1”和“Med2”结尾.如果只有“Med1”被标记删除,我将最终得到“Med1”和“Med2”和额外的“Med2”.如果没有标记删除,我将最终得到“Med1”和“Med2”两个.

#patient.rb
class Patient < ActiveRecord::Base
has_many :procedures
has_many :medications,dependent: :destroy
has_many :prevIoUs_operations,dependent: :destroy

accepts_nested_attributes_for :medications,:allow_destroy => true,:reject_if => lambda { |a| a[:name].blank? },end
#views/patients/_form.html.erb
<%= form_for(@patient) do |f| %>
  <% if @patient.errors.any? %>
    <div id="error_explanation">
      <h2><%= pluralize(@patient.errors.count,"error") %> prohibited this patient from being saved:</h2>

      <ul>
      <% @patient.errors.full_messages.each do |msg| %>
        <li><%= msg %></li>
      <% end %>
      </ul>
    </div>
  <% end %>

  <%= f.fields_for :medications do |builder| %>
    <%= render "medication_fields",:f => builder %>
  <% end %>

  <div class="field">
    <%= f.label :first_name %><br>
    <%= f.text_field :first_name %>
  </div>
  <div class="field">
    <%= f.label :last_name %><br>
    <%= f.text_field :last_name %>
  </div>
  <div class="actions">
    <%= f.submit %>
  </div>
<% end %>
#views/patients/medications_fields.html
<div class="field">
  <%= f.label :name %><br>
  <%= f.text_field :name %>
</div>
<div class="field">
  <%= f.label :_destroy,"Remove Medication" %>
  <%= f.check_Box :_destroy %>
</div>
#controllers/patients_controller.rb
class PatientsController < ApplicationController
  before_action :set_patient,only: [:show,:edit,:update,:destroy]

  # GET /patients
  # GET /patients.json
  def index
    @patients = Patient.all
  end

  # GET /patients/1
  # GET /patients/1.json
  def show
  end

  # GET /patients/new
  def new
    @patient = Patient.new
    3.times { @patient.medications.build }
  end

  # GET /patients/1/edit
  def edit
  end

  # POST /patients
  # POST /patients.json
  def create
    @patient = Patient.new(patient_params)

    respond_to do |format|
      if @patient.save
        format.html { redirect_to @patient,notice: 'Patient was successfully created.' }
        format.json { render action: 'show',status: :created,location: @patient }
      else
        format.html { render action: 'new' }
        format.json { render json: @patient.errors,status: :unprocessable_entity }
      end
    end
  end

  # PATCH/PUT /patients/1
  # PATCH/PUT /patients/1.json
  def update
    respond_to do |format|
      if @patient.update(patient_params)
        format.html { redirect_to @patient,notice: 'Patient was successfully updated.' }
        format.json { head :no_content }
      else
        format.html { render action: 'edit' }
        format.json { render json: @patient.errors,status: :unprocessable_entity }
      end
    end
  end

  # DELETE /patients/1
  # DELETE /patients/1.json
  def destroy
    @patient.destroy
    respond_to do |format|
      format.html { redirect_to patients_url }
      format.json { head :no_content }
    end
    flash[:notice] = "Patient was successfully deleted."
  end

  private

    # Never trust parameters from the scary internet,only allow the white list through.
    def patient_params
      params.require(:patient).permit(:first_name,:last_name,medications_attributes: [:name,:_destroy])
    end

end

我一直非常小心,检查了一百万次:_destroy标志被允许通过强大的参数,但仍然没有骰子.

任何帮助赞赏,必须是明显的,我只是看不到.

编辑

改变这个…

# Never trust parameters from the scary internet,:_destroy])
    end

到这个…

# Never trust parameters from the scary internet,only allow the white list through.
    def patient_params
      params.require(:patient).permit!
    end

似乎工作正常,所以我仍然确定这是与强参数有关,但后者是不太安全,我敢肯定,而不是最佳实践.

解决方法

当你在做什么
# Never trust parameters from the scary internet,only allow the white list through.
def patient_params
  params.require(:patient).permit!
end

它允许您的所有属性,不推荐.这更像是一个黑客而不是解决方案.

如果你看你的问题

Rails 4删除嵌套属性,适用于创建,但不能编辑/更新

如果你看看你允许的参数

# Never trust parameters from the scary internet,only allow the white list through.
def patient_params
  params.require(:patient).permit(:first_name,:_destroy])
end

这将有助于创建病人,但不会更新或编辑他们,因为当您创建新记录时,它不需要您允许ID,但是当您想要更新或编辑记录时,您需要其ID被允许.

固定:

只需将id属性传递给允许的属性,它将为您工作

# Never trust parameters from the scary internet,only allow the white list through.
def patient_params
  params.require(:patient).permit(:id,:first_name,medications_attributes: [:id,:name,:_destroy])
end
原文链接:https://www.f2er.com/ruby/272692.html

猜你在找的Ruby相关文章