当字符串以下面的格式出现时,我想以特定格式哈希：
给定字符串：
str = 'A A = B A = B = C A = B = D A = E = F G = H G = I G = J'
#进入这样的哈希(必需的哈希模式)：
{
"A" => {
"B" => {
"C" => nil,"D" => nil
},"E" => {
"F" => nil
},},"G" => {
"H" => nil,"I" => nil,"J" => nil
}
}
我尝试了很多方法,但这是最接近的：
output = Hash.new
line_hash = Hash.new
str.each_line do |line|
arr = line.split("=")
e = arr.first.strip
line_hash[e] = {}
arr.each_with_index do |ele,i|
break unless arr[i+1]
line_hash[ele.strip] = arr[i+1] unless output.keys.include?(ele.strip)
end
output[e] = line_hash unless output.keys.include?(e)
end
解决方法
str = "A\nA = B\nA = B = C\nA = B = D\nA = E = F\nG = H\nG = I\nG = J"
curr = h = {}
str.each_line { |l|
l.chomp.split(/\s*=\s*/m).each { |c|
curr = curr[c] ||= {};
}
curr = h
}
puts h
# => {
# "A" => {
# "B" => {
# "C" => {},# "D" => {}
# },# "E" => {
# "F" => {}
# }
# },# "G" => {
# "H" => {},# "I" => {},# "J" => {}
# }
# }
我希望你能原谅我留下空的哈希值而不是叶子上的空值,以便清楚地解决问题.
要使叶子无效：
def leaves_nil! hash
hash.each { |k,v| v.empty? ? hash[k] = nil : leaves_nil!(hash[k]) }
end