long_string = <<EOS It was the best of times,It was the worst of times. EOS
返回53.为什么？空白计数？即便如此.我们怎么得到53？
这个怎么样？
def test_flexible_quotes_can_handle_multiple_lines
long_string = %{
It was the best of times,It was the worst of times.
}
assert_equal 54,long_string.size
end
def test_here_documents_can_also_handle_multiple_lines
long_string = <<EOS
It was the best of times,It was the worst of times.
EOS
assert_equal 53,long_string.size
end
是这种情况,因为％{case将每个/ n计为一个字符,并且在第一行之前认为是一个,最后一个,然后在第二行的末尾,而在EOS情况下只有一个在第1行之前和第1行之后？换句话说,为什么前者54和后者53？
解决方法
对于：
long_string = <<EOS It was the best of times,It was the worst of times. EOS String is: "It was the best of times,\nIt was the worst of times.\n" It was the best of times,=> 25 <newline> => 1 It was the worst of times. => 26 <newline> => 1 Total = 25 + 1 + 26 + 1 = 53
和
long_string = %{
It was the best of times,It was the worst of times.
}
String is:
"\nIt was the best of times,\nIt was the worst of times.\n"
#Note leading "\n"
这个怎么运作：
在<< EOS的情况下,其后面的行是字符串的一部分. <<<<<<与<<<<并且到该行的末尾将是“标记”的一部分,其确定字符串何时结束(在这种情况下,线上的EOS本身与<< EOS匹配). 在％{…}的情况下,它只是用来代替“…”的不同分隔符.因此,当你在％{之后的新行上开始字符串时,该换行符是字符串的一部分. 试试这个例子,您将看到％{…}与“…”的工作方式相同：
a = " It was the best of times,It was the worst of times. " a.length # => 54 b = "It was the best of times,It was the worst of times. " b.length # => 53