"2e10" => true

Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.

分析：

判断字符串是否满足满足某些规则，应该想到正则表达式。

public class Solution {
    public boolean isNumber(String s) {
        
        if(s == null || s.trim().length()==0)
            return false;
        String regex = "[-+]?(\\d+\\.?|\\.\\d+)\\d*(e[-+]?\\d+)?";
        if(s.trim().matches(regex))
            return true;
        return false;
    }
}