我试图找到匹配的正则表达式,如果推文是真正的提及.值得一提的是,字符串不能以“@”开头,不能包含“RT”(不区分大小写),“@”必须以单词开头.
一些例子：
function search($strings,$regexp) {
$regexp;
foreach ($strings as $string) {
echo "Sentence: \"$string\" <- " .
(preg_match($regexp,$string) ? "MATCH" : "NO MATCH") . "\n";
}
}
$strings = array(
"Hi @peter,I like your car ",// <- MATCH
"@peter I don't think so!",//<- NO MATCH: the string it's starting with @ it's a reply
"Helo!! :@ how are you!",// NO MATCH <- it's not a word,we need @(word)
"Yes @peter i'll eat them this evening! RT @peter: hey @you,do you want your pancakes?",// <- NO MATCH "RT/rt" on the string,it's a RT
"Helo!! ineed@aser.com how are you!",//<- NO MATCH,it doesn't start with @
"@peter is the best friend you could imagine. RT @juliet: @you do you know if @peter it's awesome?" // <- NO MATCH starting with @ it's a reply and RT
);
echo "Example 1:\n";
search($strings,"/(?:[[:space:]]|^)@/i");
当前输出：
Example 1: Sentence: "Hi @peter,I like your car " <- MATCH Sentence: "@peter I don't think so!" <- MATCH Sentence: "Helo!! :@ how are you!" <- NO MATCH Sentence: "Yes @peter i'll eat them this evening! RT @peter: hey @you,do you want your pancakes?" <- MATCH Sentence: "Helo!! ineed@aser.com how are you!" <- MATCH Sentence: "@peter is the best friend you could imagine. RT @juliet: @you do you know if @peter it's awesome?" <- MATCH
编辑：
I need it in regex beacause it can be used on MysqL and anothers
languages too. Im am not looking for any username. I only want to know
if the string it’s a mention or not.
这是一个应该有效的正则表达式：
原文链接：https://www.f2er.com/regex/356982.html/^(?!.*\bRT\b)(?:.+\s)?@\w+/i
说明：
/^ //start of the string
(?!.*\bRT\b) //Verify that rt is not in the string.
(?:.*\s)? //Find optional chars and whitespace the
//Note: (?: ) makes the group non-capturing.
@\w+ //Find @ followed by one or more word chars.
/i //Make it case insensitive.
