我正在尝试抓取this Wikipedia page.
我遇到一些问题,非常感谢您的协助：
Some rows have more than one name or link and I want them all to be assigned to the correct country. Is there anyway I can do that?
I want to skip the ‘Name(native)’ column. How can I do that?
If I’m scraping the ‘Name(native)’ column. I get some gibberish,is there anyway to encode that?
import requests
from bs4 import BeautifulSoup
import csv
import pandas as pd
url = 'https://en.wikipedia.org/wiki/List_of_government_gazettes'
source = requests.get(url).text
soup = BeautifulSoup(source,'lxml')
table = soup.find('table',class_='wikitable').tbody
rows = table.findAll('tr')
columns = [col.text.encode('utf').replace('\xc2\xa0','').replace('\n','') for col in rows[1].find_all('td')]
print(columns)
最佳答案
您可以使用pandas函数
原文链接：https://www.f2er.com/python/533228.htmlread_html并从DataFrames列表中获取第二个DataFrame：
url = 'https://en.wikipedia.org/wiki/List_of_government_gazettes'
df = pd.read_html(url)[1].head()
print (df)
Country/region Name \
0 Albania Official Gazette of the Republic of Albania
1 Algeria Official Gazette
2 Andorra Official Bulletin of the Principality of Andorra
3 Antigua and Barbuda Antigua and Barbuda Official Gazette
4 Argentina Official Gazette of the Republic of Argentina
Name (native) Website
0 Fletorja Zyrtare E Republikës Së Shqipërisë qbz.gov.al
1 Journal Officiel d'Algérie joradp.dz/HAR
2 Butlletí Oficial del Principat d'Andorra www.bopa.ad
3 Antigua and Barbuda Official Gazette www.legalaffairs.gov.ag
4 Boletín Oficial de la República Argentina www.boletinoficial.gob.ar
如果检查输出,则第26行有问题,因为Wiki页面中的数据也有误.
解决方案应按列名和行设置值：
df.loc[26,'Name (native)'] = np.nan