我正在列出另一个列表中存在的元素列表.有两个条件：

条件1.需要完全匹配,因此我不使用“如果x中的y”.

条件2.必须保留原始列表的顺序.

rhg_brands = ['Radisson Collection','Radisson Blu','Park Plaza','Radisson Red','Radisson']

brands_in_df = ['Radisson Collection','Radisson']

#remove brands from rhg_brands if they're not in the brands_in_df 
rhg_brands = set(rhg_brands).intersection(set(brands_in_df))  

#output:
{'Park Plaza','Radisson','Radisson Collection','Radisson Red'}

我希望输出以某种方式保留原始列表的顺序.

下面是所需输出的示例：

{'Radisson Collection',}