我有以下型号：
class LibraryEntry(models.Model): player = models.ForeignKey(Player) player_lib_song_id = models.IntegerField() title = models.CharField(max_length=200) artist = models.CharField(max_length=200) album = models.CharField(max_length=200) track = models.IntegerField() genre = models.CharField(max_length=50) duration = models.IntegerField() is_deleted = models.BooleanField(default=False) class Meta: unique_together = ("player","player_lib_song_id") def __unicode__(self): return "Library Entry " + str(self.player_lib_song_id) + ": " + self.title class BannedSong(models.Model): lib_entry = models.ForeignKey(LibraryEntry) def __unicode__(self): return "Banned Library Entry " + str(self.lib_entry.title)
我想做这样的查询：
banned_songs = BannedSong.objects.filter(lib_entry__player=activePlayer) available_songs = LibraryEntry.objects.filter(player=activePlayer).exclude(banned_songs)
基本上如果一首歌被禁止,我想把它从我的可用歌曲中排除.有没有办法在Django中这样做？
解决方法
banned_song_ids = (BannedSong.objects.filter(lib_entry__player=activePlayer)
.values_list('lib_entry',flat=True))
available_songs = (LibraryEntry.objects.filter(player=activePlayer)
.exclude('id__in' = banned_song_ids))
替代方案是：
available_songs = (LibraryEntry.objects.filter(player=activePlayer)
.filter(bannedsong__isnull = True))