postgresql – Postgres存储函数如何返回一个表

我想知道一个Postgres存储函数如何返回一个表,具有标识列.我使用返回setof returnType：

-- create employeeSearchResult returnType
create type employeeAllReturnType as
(
  id bigserial,"positionId" integer,"subjectId" bigint,"dateEngaged" date,"nextKin" text,"nrcNo" text,dob date,father text,mother text,wife text,"userId" integer,"statusId" integer,"mainCode" text,"subCode" text
);


-- Search for emmployee by name
CREATE OR REPLACE FUNCTION "employee_search_by_name"(employeeNameIN text)
returns setof employeeAllReturnType as 
$$
declare
    results record;
    resultsRow employee%rowtype;
    nameIn text;
begin
    nameIn = employeeNameIN || '%';
    for results in select 
        employee.id,-- bigserial NOT NULL,employee."positionId",-- integer,employee."subjectId",-- bigint NOT NULL,employee."dateEngaged",-- date,employee."nextKin",-- text,employee."nrcNo",employee.dob,employee.father,employee.mother,employee.wife,employee."userId",-- integer NOT NULL,employee."statusId",employee."mainCode",-- character(5) NOT NULL,employee."subCode"-- character(10),from employee,subject where employee."subjectId" = subject.id and (subject.name1 ILIKE nameIn OR subject.name2 ILIKE nameIn OR subject.name3 ILIKE nameIn OR subject.name4 ILIKE nameIn) loop
      return next results;
    end loop;
end;
$$language 'plpgsql';

并返回table()：

-- Search for emmployee by name
CREATE OR REPLACE FUNCTION "employee_search_by_name"(employeeNameIN text)
returns table (id bigserial,position integer,subject bigint,date_engaged date,next_kin text,nrc_no text,user_id integer,status_id integer,main_code text,sub_code text) as 
$$
declare
    results record;
    resultsRow employee%rowtype;
    nameIn text;
begin
    nameIn = employeeNameIN || '%';
    for results in select 
        employee.id,subject where employee."subjectId" = subject.id and (subject.name1 ILIKE nameIn OR subject.name2 ILIKE nameIn OR subject.name3 ILIKE nameIn OR subject.name4 ILIKE nameIn) loop
      return next results;
    end loop;
end;
$$language 'plpgsql';

但都有以下格式的输出：

"(1,1,2011-12-01,Timea,fg1254,1981-12-27,moses,sarada,timea,"ADM  ","1         ")"
"(37,3,10,2011-11-11,s,"OP   ","1         ")"

有没有我可以输出如表的选择结果的输出？

"1";1;1;"2011-12-01";"Timea";"fg1254";"1981-12-27";"moses";"sarada";"timea";1;1;"ADM  ";"1         "

这样从前端处理结果数据就不需要一个解析器.

你应该像这样查询你的函数：

SELECT * FROM employee_search_by_name('Bob');

另外,为了简化您的功能,您可以查看RETURN QUERY EXECUTE ...的结构.并且不需要引用plpgsql关键字.

原文链接：https://www.f2er.com/postgresql/191710.html

postgresql – Postgres存储函数如何返回一个表

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