我有一个3层的形式:
第一层是游戏的容器:
原文链接:https://www.f2er.com/php/139593.html第一层是游戏的容器:
class GameListType extends AbstractType { public function buildForm(FormBuilderInterface $builder,array $options) { $builder->add('games','collection',array( 'required' => false,'allow_add' => true,'prototype' => true,'by_reference' => false,'type' => new GameBetType(),)) ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { parent::setDefaultOptions($resolver); $resolver->setDefaults(array( 'cascade_validation' => true,)); } }
第二层是游戏本身,因为我不打算改变游戏,而是打赌,它只包括下注的形式:
class GameBetType extends AbstractType { public function buildForm(FormBuilderInterface $builder,array $options) { $builder->add('bet',new BetType()); } public function setDefaultOptions(\Symfony\Component\OptionsResolver\OptionsResolverInterface $resolver) { parent::setDefaultOptions($resolver); $resolver->setDefaults(array( 'data_class' => 'Strego\TippBundle\Entity\Game','cascade_validation' => true,)); } }
第三层是下注的形式:
class BetType extends AbstractType { public function buildForm(FormBuilderInterface $builder,array $options) { $builder->add('scoreT1','text') ->add('scoreT2','text'); ; } public function setDefaultOptions(\Symfony\Component\OptionsResolver\OptionsResolverInterface $resolver) { parent::setDefaultOptions($resolver); $resolver->setDefaults(array( 'data_class' => 'Strego\TippBundle\Entity\Bet',)); } }
问题是,如果第三级有验证约束,根表单总是有效的,但是如果我具体验证了下注实体,我的控制器中会得到正确的违规列表:
// Form processing $form = $this->createForm(new GameListType(),$entity); $request = $this->getRequest(); if ($request->getMethod() == 'POST') { $form->bind($request); $entity = $form->getData(); if ($form->isValid()) { foreach ($entity->getGames() as $game) { if($game->hasBet()){ $bet = $game->getBet(); $bet->setUser($user); $validator = $this->container->get('validator'); $errors = $validator->validate($bet); var_dump($errors) //<-- i see there are errors if(count($errors) == 0){ print($bet. ' gets persisted<br>'); $em->persist($bet); } } } $em->flush(); } }
另一个问题是,即使我不调用$em-> persist($bet),实体就会被持久化.我看不到输出中描述的输出
print($bet.'gets persisted<br>');
但表单输入仍然保留在数据库中.
所以我的两个问题:
>如果验证失败,如果赌注失败,我如何得到错误(我不希望整个表单无效,因为3个赌注中只有1个无效).
即使我不叫$em-persist($bet),为什么这个赌注持续下去,这是绑定发生的一些魔法吗?