php – Dijkstra算法优化/缓存

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我有以下Dijkstra算法,有3个输入变量(开始,停止和时间).完成需要大约0.5-1秒.我的托管服务提供商说它使用了太多资源,我应该实现一些缓存机制.我的问题是,怎么样?

因为我有3个变量,如果只有其中一个变化 – 整个结果是不同的(因为我有一些额外的陈述与时间,从来没有).那么如何实现一些缓存机制或做一些优化呢?

我有1700个节点.

<?PHP require_once("../includes/db_connection.PHP"); ?>
<?PHP require("../includes/functions.PHP"); ?>
<?PHP require("../includes/global_variables.PHP"); ?>
<?PHP
    // Function to put "maxValues" into time (in my case 10 000 because I know it can't take longer than that from source to end node)
    function array_push_key(&$array,$key,$value) {
        $array[$key] = $value;
    }

    // Start the counter
    $timeM = microtime(); $timeM = explode(' ',$timeM); $timeM = $timeM[1] + $timeM[0]; $start = $timeM;

    // Get provided values
    $startStop = $_GET["start"];
    $endStop = $_GET["end"];
    $startTime = $_GET["time"];

    // Initialize arrays
    $time = array();
    $prevIoUsNode = array();
    $allStops = array();

    // [5] = 119 --> You can get to stop no. 5 by line no. 119
    // line to source node is 0
    $lineToThisStop = array();
    $lineToThisStop[$startStop] = 0;

    // Populate arrays
    $result=MysqL_query("SELECT stop_id FROM db_stops",$connection);
    potvrdi_unos($result);
    $counter = 0;
    while($rows = MysqL_fetch_array($result)){
        array_push_key($time,$rows["stop_id"],10000);
        array_push($allStops,$rows["stop_id"]);
        // Locate startStop in the allStops array to unset it few lines later
        if ($rows["id"] == $startStop) {
            $poz = $brojac;
        }
        $counter++;
    }

    // Set starting time to starting stop
    $time[$startStop] = $startTime;
    // Set it activeNode
    $activeNode = $startStop;

    // Unset it in allStops array (so it doens't have to be checked later)
    unset($allStops[$poz]);
    $allStops = array_values($allStops);

    // I can put "while (true)" because all nodes are connected in "one piece",there is NO UNCONNECTED nodes
    while (true) {       
        $result=MysqL_query("SELECT route_id,next_stop FROM db_stop_times WHERE stop_id = $activeNode",$connection);
        potvrdi_unos($result);

        while($rows = MysqL_fetch_array($result)) {         
            // Draw paths from active node to all other (connected) stops
            $nextStopArray = $rows["next_stop"];

            // nextStopArray is something like "0,34,123,3123,213" - those are all stops from current,active node/stop
            $nextStopArray = explode(",",$nextStopArray);

            // sometimes it's just "4" to convert it into array
            if (!is_array($nextStopArray)) {
                $nextStopArray[0] = $nextStopArray;
            }

            for ($p = 0; $p < sizeof($nextStopArray); $p++) {
                $nextStop = $nextStopArray[$p];

                $walkToTheStop = false;

                // Few checks                   
                if ($p == 0) {
                    if ($nextStop != 0) {
                        $pathDuration = 2;                          

                        if ($lineToThisStop[$activeNode] != $rows["route_id"]) {
                            $pathDuration = $pathDuration * 2;
                        }
                    }
                } else {
                    $walkToTheStop = true;

                    $pathDuration = 1;                          
                }

                // If that's shortest path from ActiveNode to nextStop insert it into it's time array (time to get to that stop)
                if (($pathDuration + $time[$activeNode]) < $time[$nextStop]) {
                    $time[$nextStop] = $pathDuration + $time[$activeNode];

                    array_push_key($prevIoUsNode,$nextStop,$activeNode);

                    // Some aditional records (5000 means "you must walk to that stop")
                    if ($walkToTheStop) {
                        $lineToThisStop[$nextStop] = 5000;
                    } else {
                        $lineToThisStop[$nextStop] = $rows["route_id"];
                    }
                }
            }           
        }

        // Traži slijedeću stanicu (vrh) s najmanjom vrijednosti        
        $lowestValue = 10000 + 1;
        for ($j = 0; $j < sizeof($allStops); $j++) {
            if ($time[$allStops[$j]] < $lowestValue) {
                $lowestValue = $time[$allStops[$j]];                        
                $activeNode = $allStops[$j];

                // Record it's position so I can unset it later
                $activeNodePosition = $j;
            }
        }

        // Unset the active node from the array - so loop before will be shorter every time for one node/stop
        unset($allStops[$activeNodePosition]);
        $allStops = array_values($allStops);

        // If you get to the end stop,feel free to break out of the loop
        if ($activeNode == $endStop) {
            break;
        }
    }

    // How long did it take?
    $timeM = microtime(); $timeM = explode(' ',$timeM); $timeM = $timeM[1] + $timeM[0]; $finish = $timeM;

    $total_time = round(($finish - $start),4);
    echo 'Total time '.$total_time.' seconds.'."<br />";
?>

<?PHP require_once("../includes/close_connection.PHP"); ?>
微观优化,但不做:
for ($p = 0; $p < sizeof($nextStopArray); $p++) { 
   ...
}

在循环之前计算sizeof($nextStopArray),否则你每次迭代都在计算(并且这个值没有被改变)

$nextStopArraySize = sizeof($nextStopArray);
for ($p = 0; $p < $nextStopArraySize; ++$p) { 
   ...
}

有几个地方应该改变.

如果你迭代几千次,$p比$p快

但是要对功能进行分析……找出执行时间最长的部分,然后进行优化.

编辑

摆脱array_push_key作为一个函数,简单地执行它内联…它会花费你不必要的函数调用否则

在while(true)循环之外构建数据库中所有节点的数组…检索单个SQL查询中的所有数据并构建查找数组.

更换

for ($p = 0; $p < sizeof($nextStopArray); $p++) {

$nextStopArraySize = sizeof($nextStopArray);
$p = -1
while (++$p < $nextStopArraySize) { 
   ...
}

也可能更快地证明(只需检查逻辑是否循环了正确的次数).

原文链接:https://www.f2er.com/php/138553.html

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