SELECT b.id,b.title,b.description 
FROM memberships AS m
JOIN blogs AS b ON b.id = m.blog_id 
WHERE m.user_id = ? 
ORDER BY m.created
LIMIT 0,30

(此查询有效并返回结果)

成员资格是博客和用户之间的链接表.这很简单id | blog_id | user_id |事务.

这是我到目前为止所拥有的：

// $table = Zend_Db_Table instance,$id = a user id
$select = $table->select()
->from(array('m' => 'memberships'),array('b.id','b.title','b.description'))
->join(array('b' => 'blogs'),'b.id = m.blog_id')
->where('m.user_id = ?',(int) $id)
->order('m.created DESC')
->limit(0,30);

这是我得到的(对我来说很奇怪)错误：

#0: Select query cannot join with another table

Occurred on line 211 of D:\...\library\Zend\Db\Table\Select.PHP.

谢谢你的帮助.