php – jQuery提交表单两次

我知道这个问题已经被回答了几百次,但是我已经遇到了大量潜在的解决方案,但它们似乎都没有在我的实例中起作用.

以下是我提交表格的表格和代码.它会触发PHP脚本.现在我知道脚本本身不是提交的原因,因为我手动尝试了表单,它只提交一次.

jQuery代码的第一部分涉及打开一个灯箱并从下面的表中提取值,我已将其包含在内,无论出于何种原因它都是潜在的问题.

jQuery代码：

$(document).ready(function(){
    $('.form_error').hide();
    $('a.launch-1').click(function() { 
        var launcher = $(this).attr('id'),launcher = launcher.split('_');
        launcher,launcher[1],$('td .'+launcher[1]);
        $('.'+launcher[1]).each(function(){
            var field = $(this).attr('data-name'),fieldValue = $(this).html();
            if(field === 'InvoiceID'){
                $("#prevIoUspaymentsload").load("functions/invoicing_payments_received.PHP?invoice="+fieldValue,null,function() {
                    $("#prevIoUspaymentsloader").hide();
                });
            } else if(field === 'InvoiceNumber'){
                $("#addinvoicenum").html(fieldValue);
            }
            $('#'+field).val(fieldValue);
        });
    });
    $("#addpayment_submit").click(function(event) {         
        $('.form_error').hide();  
        var amount = $("input#amount").val();  
        if (amount == "") {  
            $("#amount_error").show();  
            $("input#amount").focus();  
            return false;
        }
        date = $("input#date").val();  
        if (date == "") {  
            $("#date_error").show();  
            $("input#date").focus(); 
            return false;
        } 
        credit = $("input#credit").val(); 
        invoiceID = $("input#InvoiceID").val(); 
        by = $("input#by").val(); 
        dataString = 'amount='+ amount + '&date=' + date + '&credit=' + credit + '&InvoiceID=' + invoiceID + '&by=' + by;
        $.ajax({
            type: "POST",url: "functions/invoicing_payments_make.PHP",data: dataString,success: function(result) {
                if(result == 1){                    
                    $('#payment_window_message_success').fadeIn(300);
                    $('#payment_window_message_success').delay(5000).fadeOut(700);
                    return false;
                } else {
                    $('#payment_window_message_error_mes').html(result);
                    $('#payment_window_message_error').fadeIn(300);
                    $('#payment_window_message_error').delay(5000).fadeOut(700);
                    return false;
                }
            },error: function() {
                $('#payment_window_message_error_mes').html("An error occured,form was not submitted");
                $('#payment_window_message_error').fadeIn(300);
                $('#payment_window_message_error').delay(5000).fadeOut(700);
            }
        });
        return false;
    });
});

这是html表单：

<div id="makepayment_form">
  <form name="payment" id="payment" class="halfBoxform">
    <input type="hidden" name="InvoiceID" id="InvoiceID" />
    <input type="hidden" name="by" id="by" value="<?PHP echo $userInfo_ID; ?>" />
    <fieldset>
      <label for="amount" class="label">Amount:</label>
      <input type="text" id="amount" name="amount" value="0.00" />
      <p class="form_error clearb red input" id="amount_error">This field is required.</p> 
      <label for="credit" class="label">Credit:</label>
      <input type="text" id="credit" name="credit" />
      <label for="amount" class="label">Date:</label>
      <input type="text" id="date" name="date" />
      <p class="form_error clearb red input" id="date_error">This field is required.</p>
    </fieldset>
    <input type="submit" class="submit" value="Add Payment" id="addpayment_submit">
  </form>
</div>

希望有人能帮忙,因为它让我疯狂.谢谢.

有时,您不仅要阻止处理事件的默认行为,还要防止执行任何下游事件处理程序链.
这可以通过在 event.preventDefault()之外调用 event.stopImmediatePropagation()来完成.

示例代码：

$("#addpayment_submit").on('submit',function(event) {
  event.preventDefault();
  event.stopImmediatePropagation();
});

原文链接：https://www.f2er.com/php/133452.html

php – jQuery提交表单两次

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