如何传递对象构造函数的引用,并允许该对象更新该引用？
class A{
private $data;
function __construct(&$d){
$this->data = $d;
}
function addData(){
$this->data["extra"]="stuff";
}
}
// Somewhere else
$arr = array("seed"=>"data");
$obj = new A($arr);
$obj->addData();
// I want $arr to contain ["seed"=>"data","extra"=>"stuff"]
// Instead it only contains ["seed"=>"data"]
您必须将它存储在任何地方作为参考.
原文链接：https://www.f2er.com/php/133369.htmlfunction __construct (&$d) {
$this->data = &$d; // the & here
}
