<?PHP

if (isset($_POST['submit']))
  {
 //if "email" is filled out,proceed

$name=  MysqL_real_escape_string($_POST['name']);
$phone=  MysqL_real_escape_string($_POST['phone']);

 $to = "admin@gmail.com";
$subject = "Customer Intrested";
$message = "Buyer Information and Intrested in land.";
$message.= "Customer Name :".$name."\n";
$message.= "Customer Phone :".$phone."\n";  

$mail=mail($to,"Subject: $subject",$message );
if($mail){
 echo "success";
  }else{
 echo "Failed."; 
  }
?>

我使用上面的代码发送电子邮件但是我无法得到结果…总是显示“谢谢信息”..

我可以得到名字和电话的价值.

如何解决这个问题？