期望使用PHPUnit模拟对象的部分数组

使用()子句在 PHPUnit模拟中测试多个数组键的最佳方式是什么？

例如,要测试方法调用第二个参数是否包含一个’foo’键的数组：

$this->stubDispatcher->expects($this->once())
        ->method('send')
        ->with('className',$this->arrayHasKey('foo'));

我想做的是像$this-> arrayHasKey(‘foo’,’bar’),而实际上并不匹配数组的确切内容.

您可以直接将断言传递给 – > with(),但它们的名称不同.

有关列表,请查看源：https：//github.com/sebastianbergmann/PHPunit/blob/3.5/PHPUnit/Framework/Assert.PHP#L2097及以下.一切都不以“assert”开头,并返回一个新的PHPUnit_Framework_ *.

虽然我认为@ David的答案是有用的,我认为这种方法,使用logicalAnd()是一个更干净/更容易阅读.

$mock->expects($this->once())->method("myMethod")->with(
    $this->logicalAnd(
        $this->arrayHasKey("foo"),$this->arrayHasKey("bar")
    )
);

工作实例

<?PHP


class MyTest extends PHPUnit_Framework_TestCase {

    public function testWorks() {
        $mock = $this->getMock("stdClass",array("myMethod"));
        $mock->expects($this->once())->method("myMethod")->with(
            $this->logicalAnd(
                $this->arrayHasKey("foo"),$this->arrayHasKey("bar")
            )
        );
        $array = array("foo" => 1,"bar" => 2);
        $mock->myMethod($array);
    }

    public function testFails() {
        $mock = $this->getMock("stdClass",$this->arrayHasKey("bar")
            )
        );
        $array = array("foo" => 1);
        $mock->myMethod($array);
    }

}

产量

PHPunit assertArrayKey.PHP 
PHPUnit 3.5.13 by Sebastian Bergmann.

.F

Time: 0 seconds,Memory: 6.50Mb

There was 1 failure:

1) MyTest::testFails
Expectation Failed for method name is equal to <string:myMethod> when invoked 1 time(s)
Parameter 0 for invocation stdClass::myMethod(array( <string:foo> => <integer:1> )) does not match expected value.
Failed asserting that an array has the key <string:bar>.

/home/edo/test/assertArrayKey.PHP:27

原文链接：https://www.f2er.com/php/131298.html

期望使用PHPUnit模拟对象的部分数组

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