我想查询一个集合并获取不到3小时前创建的文档.
$realtime = date("Y-m-d H:i:s");
$mongotime = New Mongodate(strtotime($realtime));
$mongotime = $mongotime - 3 hours; //PSEUDOCODE
$some_condition = array('time' => array('$lt'=>$mongotime) );
$result = $db->collection->find( $some_condition );
是否有一种有效的方式
$some_condition
部分没有在PHP中使用IF语句？
我找到了解决方案.
原文链接：https://www.f2er.com/php/130633.html$diff = 60 * 60 * 3; //3 hours in seconds
$mongotime = New Mongodate(time()-$diff);
$condition = array('time' => array('$lt'=>$mongotime) );
$result = $db->collection->find( $condition );
