我有这个代码获取页面的
HTML源代码：
$page = file_get_contents('http://example.com/page.html');
$page = htmlentities($page);
<strong>technorati.com</strong><br /> Connection Failed<br /><br />Pinging <strong>icerocket.com</strong><br /> Connection Failed<br /><br />Pinging <strong>weblogs.com</strong><br /> Done<br /><br />Pinging <strong>newsgator.com</strong><br /> Done<br /><br />Pinging <strong>blo.gs</strong><br /> Done<br /><br />Pinging <strong>Feedburner.com</strong><br /> Done<br /><br />Pinging <strong>blogstreet.com</strong><br /> Done<br /><br />Pinging <strong>my.yahoo.com</strong><br /> Connection Failed<br /><br />Pinging <strong>moreover.com</strong><br /> Connection Failed<br /><br />Pinging <strong>newsisfree.com</strong><br /> Done<br />
有没有办法可以从源代码中删除它并将其存储在变量中,所以它看起来像这样：
technorati.com Connection Failed
icerocket.com Connection Failed
eblogs.com Done
Ect.
因为页面是动态的,这就是我遇到问题的原因.我可以搜索源中的每个站点吗？但那我怎么得到它之后的结果呢？ (连接失败/完成)
非常感谢您的帮助！
我尝试使用简单的HTML DOM PHP库来抓取多个站点,可以在这里获得：
http://simplehtmldom.sourceforge.net/
原文链接：https://www.f2er.com/php/130313.html然后使用这样的代码：
<?PHP include_once 'simple_html_dom.PHP'; $url = "http://slashdot.org/"; $html = file_get_html($url); //remove additional spaces $pat[0] = "/^\s+/"; $pat[1] = "/\s{2,}/"; $pat[2] = "/\s+\$/"; $rep[0] = ""; $rep[1] = " "; $rep[2] = ""; foreach($html->find('h2') as $heading) { //for each heading //find all spans with a inside then echo the found text out echo preg_replace($pat,$rep,$heading->find('span a',0)->plaintext) . "\n"; } ?>
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