我们有2个非常简单的SELECT语句：
SELECT value from table where date between DATE1 and DATE2 SELECT value from table where date between DATE3 and DATE4
我们需要一种方法来编写单个sql语句,它将获得从这两个sql语句返回的“值”的差异.
我们尝试了以下但是没有成功：
SELECT value from table where date between DATE1 and DATE2 minus SELECT value from table where date between DATE3 and DATE4
任何建议都非常感谢.
未经测试但应该工作：
原文链接：https://www.f2er.com/oracle/205167.htmlSELECT
(SELECT value from table where date between DATE1 and DATE2) -
(SELECT value from table where date between DATE3 and DATE4)
FROM dual;
假设您的SELECT值保证返回单个值
