我需要根据不是主键的字段创建关系.许多如何执行此操作的示例基于一对多和多对多关系.我尝试过以下建议但没有成功
Relation in YII with not “ID” as primary key
Yii CActiveRecord: find related data,but not using the primary key
Yii Relations with non-Primary keys
Yii Model Relation Join (HAS_ONE)
我有以下表结构:
+------+---------+-----------+
| id | name | status_id |
+------+---------+-----------+
| 1 | service1| 1 |
+------+---------+-----------+
| 2 | service2| 2 |
+------+---------+-----------+
这是我的表active_service.我也有下表
+----------+----------+---------------------+-----------+
|id |related_id|related_text | text |
+----------+----------+---------------------+-----------+
|65 |1 |ActiveServices_status| Open |
+----------+----------+---------------------+-----------+
|72 |2 |ActiveServices_status| Active |
+----------+----------+---------------------+-----------+
|102 |3 |ActiveServices_status| Closed |
+----------+----------+---------------------+-----------+
这是我的related_fields表
此表包含用于下拉列表等的所有字段.related_text告诉我们它的用途,而related_id是状态的id,这是我需要链接的字段.因此,active_service表中的status_id与满足条件的related_fields表的related_id字段相关,即related_text设置为ActiveServices_status.我将如何创建这种关系.这是我迄今为止所做的最好的例子(在ActiveServices模型中).
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'rl_status'=>array(self::BELONGS_TO,'RelatedFields','status_id','condition'=>'related_text = "ActiveServices_status"','on'=>'status_id = related_id'),);
}
任何帮助,将不胜感激.
最佳答案
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