mysql – 显然fetch返回NULL

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我正在学习存储过程,mysql中的游标,我偶然发现它:@H_502_2@

@H_502_2@

delimiter //

CREATE PROCEDURE some_func()
BEGIN
    DECLARE link_rewrite VARCHAR(255);
    DECLARE link_rewrite_cursor CURSOR FOR SELECT link_rewrite FROM prod;

    OPEN link_rewrite_cursor;

    SET @count = 0;

    WHILE @count < 10 DO
        FETCH link_rewrite_cursor INTO link_rewrite;
        SELECT link_rewrite;
        set @count = @count + 1;
    END WHILE;

    CLOSE link_rewrite_cursor;

END//

delimiter ;

我的问题是:为什么SELECT link_rewrite总是返回NULL(在prod表中有9000行). SELECT link_rewrite FROM prod返回很多行(9000行).

最佳答案
您应避免对多个不同的事物使用相同的名称.具体来说,为变量指定与您选择的列不同的名称.例如,如果重命名变量v_link_rewrite,那么它可能会起作用:@H_502_2@

@H_502_2@

delimiter //

DROP PROCEDURE IF EXISTS some_func //

CREATE PROCEDURE some_func()
BEGIN
    DECLARE v_link_rewrite VARCHAR(255);
    DECLARE link_rewrite_cursor CURSOR FOR SELECT link_rewrite FROM prod;

    OPEN link_rewrite_cursor;

    SET @count = 0;

    WHILE @count < 10 DO
        FETCH link_rewrite_cursor INTO v_link_rewrite;
        SELECT v_link_rewrite;
        set @count = @count + 1;
    END WHILE;

    CLOSE link_rewrite_cursor;

END//

delimiter ;
原文链接:https://www.f2er.com/mysql/434088.html

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